1 Introduction and preliminaries

Iterative differential equation, as a special type of functional differential equations, in which the deviating argument depends on the state [19]. Many researchers have concentrated on studying first order iterative functional differential equations by different approaches such as Picard’s successive approximation, fixed point theory and the technique of nonexpansive operators, see [2, 8, 13, 21]. But the literature related to the second and higher order is very less since the presence of the iterates increases the difficulty of studying them, see [5,6,7, 11, 12, 15,16,17,18, 20]. This motivates us to study the following second order iterative functional boundary value problem on time scales

$$\begin{aligned} \mathtt {z}^{\Delta \Delta }(\mathtt {s})+\mathtt {g}\big (\mathtt {s},\mathtt {z}(\mathtt {s}),\mathtt {z}^{[2]}(\mathtt {s}),\mathtt {z}^{[3]}(\mathtt {s}),\cdot \cdot \cdot ,\mathtt {z}^{[n]}(\mathtt {s})\big )=0,~\mathtt {s}\in [a,b]_{\mathbb {T}}, \end{aligned}$$
(1)

subject to the two-point boundary conditions

$$\begin{aligned} \mathtt {z}(a)=\mathtt {z}_a,~\mathtt {z}(\upsigma ^2(b))=\mathtt {z}_b, \end{aligned}$$
(2)

where \(\mathbb {T}\) is a time scale, \(\mathtt {g}:[a,b]_\mathbb {T}\times \mathbb {R}^n\rightarrow \mathbb {R}\) is a continuous function and \(\mathtt {z}^{[2]}(\mathtt {s})=\mathtt {z}(\mathtt {z}(\mathtt {s})),\cdot \cdot \cdot ,\mathtt {z}^{[n]}(\mathtt {s})=\mathtt {z}^{[n-1]}(\mathtt {z}(\mathtt {s})).\) For more details about the theory of time scales, refer to [1, 3]. By applying Schauder fixed point theorem and contraction mapping principle, we establish the existence and uniqueness of solutions to the BVP (1)–(2). Equation (1) in real continuous time scales describes diffusion phenomena with a source or a reaction term [12]. We refer the interested reader to [9, 10, 14] and the references therein for more details.

The commonly used technique in the theory of BVPs on time scales involving transforming the BVP (1)–(2) as an equivalent integral equation (see, Chapter 7 of [4])

$$\begin{aligned}&\mathtt {z}(\mathtt {s})=\mathtt {z}_a+\frac{\mathtt {z}_b-\mathtt {z}_a}{\upsigma ^2(b)-a}(\mathtt {s}-a) \nonumber \\&\quad +\int _a^{\upsigma (b)}\mathtt {G}(\mathtt {s},\mathtt {t})\mathtt {g}\big (\mathtt {t},\mathtt {z}(\mathtt {t}),\mathtt {z}^{[2]}(\mathtt {t}),\mathtt {z}^{[3]}(\mathtt {t}),\cdot \cdot \cdot ,\mathtt {z}^{[n]}(\mathtt {t})\big )\Delta \mathtt {t},~\mathtt {s}\in [a,\upsigma ^2(b)]_\mathbb {T}, \end{aligned}$$
(3)

where

$$\begin{aligned} \mathtt {G}(\mathtt {s}, \mathtt {t})=\frac{1}{\upsigma ^2(b)-a}\left\{ \begin{array}{ll} (\mathtt {s}-a)(\upsigma ^2(b)-\upsigma (t)),~~if~~\, \mathtt {s}\le \mathtt {t},\\ (\upsigma (t)-a)(\upsigma ^2(b)-\mathtt {s}),~~if~~ \upsigma (\mathtt {t})\le \mathtt {s}. \end{array}\right. \end{aligned}$$
(4)

Moreover, we note that \(\mathtt {G}(\mathtt {s},\mathtt {t})\) is nonnegative on \([a,\upsigma ^2(b)]_\mathbb {T}\times [a,b]_\mathbb {T}\) and

$$\begin{aligned} \mathtt {G}(\mathtt {s},\mathtt {t})\le \mathtt {G}(\upsigma (\mathtt {t}),\mathtt {t}),~(\mathtt {s},\mathtt {t})\in [a,\upsigma ^2(b)]_\mathbb {T}\times [a,b]_\mathbb {T}. \end{aligned}$$
(5)

We difine

$$\begin{aligned} \mathtt {M}=\max _{\mathtt {s}\in [a,\upsigma ^2(b)]_\mathbb {T}}\int _a^{\upsigma (b)}\mathtt {G}(\mathtt {s},\mathtt {t})\Delta \mathtt {t}. \end{aligned}$$
(6)

Lemma 1

For any \(\mathtt {s}_1,\mathtt {s}_2\in [a,\upsigma ^2(b)]_\mathbb {T},\) the Green’s function (4) satisfies

$$\begin{aligned} \int _a^{\upsigma ^2(b)}\vert \mathtt {G}(\mathtt {s}_1,\mathtt {t})-\mathtt {G}(\mathtt {s}_2,\mathtt {t})\vert \Delta \mathtt {t}\le \mathtt {N}\vert \mathtt {s}_1-\mathtt {s}_2\vert , \end{aligned}$$

where \(\mathtt {N}=4(\upsigma ^2(b)-a).\)

Proof

Set \(\mathtt {G}_1(\mathtt {s},\mathtt {t})=\frac{(\mathtt {s}-a)(\upsigma ^2(b)-\upsigma (t))}{\upsigma ^2(b)-a}\) and \(\mathtt {G}_2(\mathtt {s},\mathtt {t})=\frac{(\upsigma (t)-a)(\upsigma ^2(b)-\mathtt {s})}{\upsigma ^2(b)-a}.\) Let \(\mathtt {s}_1,\mathtt {s}_2\in [a,\upsigma ^2(b)]_\mathbb {T}\) with \(\mathtt {s}_2\le \mathtt {s}_1.\) Then

$$\begin{aligned} \begin{aligned} \int _a^{\mathtt {s}_2}\vert \mathtt {G}_1(\mathtt {s}_1,\mathtt {t})-\mathtt {G}_1(\mathtt {s}_2,\mathtt {t})\vert \Delta \mathtt {t}&\,=\frac{1}{\upsigma ^2(b)-a}\int _a^{\mathtt {s}_2}\vert (\mathtt {s}_1-a)(\upsigma ^2(b)-\upsigma (t))\\&\quad -(\mathtt {s}_2-a)(\upsigma ^2(b)-\upsigma (t))\vert \Delta \mathtt {t}\\&\,\le \frac{1}{\upsigma ^2(b)-a}\vert \mathtt {s}_1-\mathtt {s}_2\vert \int _a^{\mathtt {s}_2}\vert (\upsigma ^2(b)-\upsigma (t))\vert \Delta \mathtt {t}\\&\,\le \frac{1}{\upsigma ^2(b)-a}\vert \mathtt {s}_1-\mathtt {s}_2\vert \int _a^{\mathtt {s}_2}\vert (\upsigma ^2(b)-a)\vert \Delta \mathtt {t}\\&\,\le (\upsigma ^2(b)-a)\vert \mathtt {s}_1-\mathtt {s}_2\vert ,\\ \int _{\mathtt {s}_2}^{\mathtt {s}_1}\vert \mathtt {G}_1(\mathtt {s}_1,\mathtt {t})-\mathtt {G}_2(\mathtt {s}_2,\mathtt {t})\vert \Delta \mathtt {t}&\,=\frac{1}{\upsigma ^2(b)-a}\int _{\mathtt {s}_2}^{\mathtt {s}_1}\vert (\mathtt {s}_1-a)(\upsigma ^2(b)-\upsigma (t))\\&\quad -(\upsigma (t)-a)(\upsigma ^2(b)-\mathtt {s}_2)\vert \Delta \mathtt {t}\\&\,\le \frac{1}{\upsigma ^2(b)-a}\int _{\mathtt {s}_2}^{\mathtt {s}_1}(\mathtt {s}_1-a)(\upsigma ^2(b)-\upsigma (t))\Delta \mathtt {t}\\&\quad +\frac{1}{\upsigma ^2(b)-a}\int _{\mathtt {s}_2}^{\mathtt {s}_1}(\upsigma (t)-a)(\upsigma ^2(b)-\mathtt {s}_2)\Delta \mathtt {t}\\&\,\le \int _{\mathtt {s}_2}^{\mathtt {s}_1}(\mathtt {s}_1-a)\Delta \mathtt {t}+\int _{\mathtt {s}_2}^{\mathtt {s}_1}(\upsigma (t)-a)\Delta \mathtt {t}\\&\,\le 2(\upsigma ^2(b)-a)\vert \mathtt {s}_1-\mathtt {s}_2\vert \end{aligned} \end{aligned}$$

and

$$\begin{aligned} \begin{aligned} \int _{\mathtt {s}_1}^{\upsigma ^2(b)}\vert \mathtt {G}_2(\mathtt {s}_1,\mathtt {t})-\mathtt {G}_2(\mathtt {s}_2,\mathtt {t})\vert \Delta \mathtt {t}&\,=\frac{1}{\upsigma ^2(b)-a}\int _a^{\mathtt {s}_2}\vert (\upsigma (t)-a)(\upsigma ^2(b)-\mathtt {s}_1)\\&\quad -(\upsigma (t)-a)(\upsigma ^2(b)-\mathtt {s}_2)\vert \Delta \mathtt {t}\\&\,\le \frac{1}{\upsigma ^2(b)-a}(\upsigma (t)-a)\int _a^{\mathtt {s}_2}\vert \mathtt {s}_1-\mathtt {s}_2\vert \Delta \mathtt {t}\\&\,\le (\upsigma ^2(b)-a)\vert \mathtt {s}_1-\mathtt {s}_2\vert . \end{aligned} \end{aligned}$$

Thus,

$$\begin{aligned}&\int _a^{\upsigma ^2(b)}\vert \mathtt {G}(\mathtt {s}_1,\mathtt {t})-\mathtt {G}(\mathtt {s}_2,\mathtt {t})\vert \Delta \mathtt {t}\\&\quad =\int _a^{\mathtt {s}_2}\vert \mathtt {G}_1(\mathtt {s}_1,\mathtt {t})-\mathtt {G}_1(\mathtt {s}_2,\mathtt {t})\vert \Delta \mathtt {t} +\int _{\mathtt {s}_2}^{\mathtt {s}_1}\vert \mathtt {G}_1(\mathtt {s}_1,\mathtt {t})-\mathtt {G}_2(\mathtt {s}_2,\mathtt {t})\vert \Delta \mathtt {t}\\&\qquad \quad +\int _{\mathtt {s}_1}^{\upsigma ^2(b)}\vert \mathtt {G}_2(\mathtt {s}_1,\mathtt {t})-\mathtt {G}_2(\mathtt {s}_2,\mathtt {t})\vert \Delta \mathtt {t}\le 4(\upsigma ^2(b)-a)\vert \mathtt {s}_1-\mathtt {s}_2\vert . \\ \end{aligned}$$

\(\square \)

Consider the function space

$$\begin{aligned} \complement [a,\upsigma ^2(b)]=\{\mathtt {z}\,|\,\mathtt {z}:[a,\upsigma ^2(b)]_\mathbb {T}\rightarrow \mathbb {R}~\text {is}~\text {continuous}\} \end{aligned}$$

and for \(\mathtt {L}>0,\) define

$$\begin{aligned} \mathscr {B}(\mathtt {L})=\{\mathtt {z}\in \complement [a,\upsigma ^2(b)]\,|\,\Vert \mathtt {z}\Vert \le \mathtt {L},\,\forall \,\mathtt {s}\in [a,\upsigma ^2(b)]_\mathbb {T}\}. \end{aligned}$$

Then \(\mathscr {B}(\mathtt {L})\) is a Banach space with the norm

$$\begin{aligned} \Vert \mathtt {z}\Vert =\max _{\mathtt {s}\in [a,\upsigma ^2(b)]_\mathbb {T}}\vert \mathtt {z}(\mathtt {s})\vert . \end{aligned}$$

For \(\mathtt {L}>0\) and \(\Bbbk >0,\) define the set

$$\begin{aligned}&\mathscr {B}(\mathtt {L},\Bbbk )=\{\mathtt {z}\in \mathscr {B}(\mathtt {L})\,|\,\Vert \mathtt {z}\Vert \le \mathtt {L}~\text {and}~\vert \mathtt {z}(\mathtt {s}_1)\\&\quad -\mathtt {z}(\mathtt {s}_2)\vert \le \Bbbk \vert \mathtt {s}_1-\mathtt {s}_2\vert ,~\forall \,\mathtt {s}_1,\mathtt {s}_2\in [a,\upsigma ^2(b)]_\mathbb {T}\}. \end{aligned}$$

Then \(\mathscr {B}(\mathtt {L},\Bbbk )\) is a closed convex and bounded subset of \(\mathscr {B}(\mathtt {L}).\) Also, it can be seen from the definition of \(\mathscr {B}(\mathtt {L},\Bbbk )\) that for every \(\uppsi ,\upphi \in \mathscr {B}(\mathtt {L},\Bbbk ),\)

$$\begin{aligned} \Vert \uppsi ^{[\dot{\iota }]}-\upphi ^{[\dot{\iota }]}\Vert \le \sum _{\mathtt {j}=0}^{\dot{\iota }-1}\Bbbk ^\mathtt {j}\Vert \uppsi -\upphi \Vert ,~~\dot{\iota }=1,2,\cdot \cdot \cdot \end{aligned}$$
(7)

Now define an operator \(\aleph :\mathscr {B}(\mathtt {L},\Bbbk )\rightarrow \mathscr {B}(\mathtt {L})\) as

$$\begin{aligned}&(\aleph \mathtt {z})(\mathtt {s})=\mathtt {z}_a+\frac{\mathtt {z}_b-\mathtt {z}_a}{\upsigma ^2(b)-a}(\mathtt {s}-a)\nonumber \\&\quad +\int _a^{\upsigma (b)}\mathtt {G}(\mathtt {s},\mathtt {t})\mathtt {g}\big (\mathtt {t},\mathtt {z}(\mathtt {t}),\mathtt {z}^{[2]}(\mathtt {t}),\mathtt {z}^{[3]}(\mathtt {t}),\cdot \cdot \cdot ,\mathtt {z}^{[n]}(\mathtt {t})\big )\Delta \mathtt {t},~\mathtt {s}\in [a,\upsigma ^2(b)]_\mathbb {T}. \end{aligned}$$
(8)

Then \(\mathtt {z}\) is a solution of (1)–(2) if and only if \(\mathtt {z}\) is a fixed point of \(\aleph .\)

2 Existence and uniqueness of solutions

This section deals with existence and uniqueness of solutions for (1)–(2). In order to reach our goal, we assume the following condition hold:

  • \((\mathcal {H}_1)\) Let \(\upalpha _1,\upalpha _2,\cdot \cdot \cdot ,\upalpha _n\) be positive constants such that

$$\begin{aligned} \vert \mathtt {g}(\mathtt {t},\mathtt {z}_1,\mathtt {z}_2,\cdot \cdot \cdot ,\mathtt {z}_n)-\mathtt {g}(\mathtt {t},\widehat{\mathtt {z}}_1,\widehat{\mathtt {z}}_2,\cdot \cdot \cdot ,\widehat{\mathtt {z}}_n)\vert \le \sum _{\mathtt {j}=1}^{n}\upalpha _\mathtt {j}\Vert \mathtt {z}_\mathtt {j}-\widehat{\mathtt {z}}_\mathtt {j}\Vert \end{aligned}$$

Lemma 2

Suppose \((\mathcal {H}_1)\) holds. Then operator \(\aleph \) is continuous and compact on \(\mathscr {B}(\mathtt {L},\Bbbk ).\)

Proof

Let \(\mathtt {z},\widehat{\mathtt {z}}\in \mathscr {B}(\mathtt {L},\Bbbk )\) and \(\mathtt {s}\in [a,\upsigma ^2(b)]_\mathbb {T}.\) Then by \((\mathcal {H}_1),\) (6) and (7),

$$\begin{aligned} \begin{aligned} \Vert (\aleph \mathtt {z})(\mathtt {s})-(\aleph \widehat{\mathtt {z}})(\mathtt {s})\Vert&\le \,\int _a^{\upsigma (b)}\vert \mathtt {G}(\mathtt {s},\mathtt {t})\vert \Big \vert \mathtt {g}\big (\mathtt {t},\mathtt {z}(\mathtt {t}),\mathtt {z}^{[2]}(\mathtt {t}),\mathtt {z}^{[3]}(\mathtt {t}),\cdot \cdot \cdot ,\mathtt {z}^{[n]}(\mathtt {t})\big )\\&\quad -\mathtt {g}\big (\mathtt {t},\widehat{\mathtt {z}}(\mathtt {t}),\widehat{\mathtt {z}}^{[2]}(\mathtt {t}),\widehat{\mathtt {z}}^{[3]}(\mathtt {t}),\cdot \cdot \cdot ,\widehat{\mathtt {z}}^{[n]}(\mathtt {t})\big )\Big \vert \Delta \mathtt {t}\\&\le \,\int _a^{\upsigma (b)}\vert \mathtt {G}(\mathtt {s},\mathtt {t})\vert \sum _{\mathtt {j}=1}^{n}\upalpha _\mathtt {j}\Vert \mathtt {z}^{[\mathtt {j}]}-\widehat{\mathtt {z}}^{[\mathtt {j}]}\Vert \Delta \mathtt {t}\\&\le \,\mathtt {M}\sum _{\mathtt {j}=1}^{n}\upalpha _\mathtt {j}\sum _{\dot{\iota }=0}^{\mathtt {j}-1}\Bbbk ^{\dot{\iota }}\Vert \mathtt {z}-\widehat{\mathtt {z}}\Vert . \end{aligned} \end{aligned}$$

Thus, \(\aleph \) is continuous. It can be seen by Arzela-Ascoli theorem that \(\aleph \) is compact. \(\square \)

Lemma 3

Suppose \((\mathcal {H}_1)\) and the following hold.

  • \((\mathcal {H}_2)\) \(2\vert \mathtt {z}_a\vert +\vert \mathtt {z}_b\vert +\mathtt {M}\left[ \mathtt {g}^\star +\mathtt {L}\sum _{\mathtt {j}=1}^{n}\upalpha _\mathtt {j}\sum _{\dot{\iota }=0}^{\mathtt {j}-1}\Bbbk ^{\dot{\iota }}\right] \le \mathtt {L},\) where \(\mathtt {g}^\star = \max _{\mathtt {t}\in [a,\upsigma ^2(b)]_\mathbb {T}}\vert \mathtt {g}(\mathtt {t},0,0,\cdot \cdot \cdot ,0)\vert .\)

Then \(\vert (\aleph \mathtt {z})(\mathtt {s})\vert \le \mathtt {L}\) for all \(\mathtt {s}\in [a,\upsigma ^2(b)]_\mathbb {T}\) and \(\mathtt {z}\in \mathscr {B}(\mathtt {L},\Bbbk ).\)

Proof

Let \(\mathtt {z}\in \mathscr {B}(\mathtt {L},\Bbbk )\) and \(\mathtt {s}\in [a,\upsigma ^2(b)]_\mathbb {T}.\) Then

$$\begin{aligned} \begin{aligned} \vert (\aleph \mathtt {z})(\mathtt {s})\vert&=\left| \mathtt {z}_a+\frac{\mathtt {z}_b-\mathtt {z}_a}{\upsigma ^2(b)-a}(\mathtt {s}-a)\right. \\&\left. \quad +\int _a^{\upsigma (b)}\mathtt {G}(\mathtt {s},\mathtt {t})\mathtt {g}\big (\mathtt {t},\mathtt {z}(\mathtt {t}),\mathtt {z}^{[2]}(\mathtt {t}),\mathtt {z}^{[3]}(\mathtt {t}),\cdot \cdot \cdot ,\mathtt {z}^{[n]}(\mathtt {t})\big )\Delta \mathtt {t}\right| \\&\le \,2\mathtt {z}_a+\mathtt {z}_b+\int _a^{\upsigma (b)}\vert \mathtt {G}(\mathtt {s},\mathtt {t})\vert \vert \mathtt {g}\big (\mathtt {t},\mathtt {z}(\mathtt {t}),\mathtt {z}^{[2]}(\mathtt {t}),\mathtt {z}^{[3]}(\mathtt {t}),\cdot \cdot \cdot ,\mathtt {z}^{[n]}(\mathtt {t})\big )\\&\quad -\mathtt {g}(\mathtt {t},0,0,\cdot \cdot \cdot ,0)\vert \Delta \mathtt {t}\\&\quad +\int _a^{\upsigma (b)}\vert \mathtt {G}(\mathtt {s},\mathtt {t})\vert \vert \mathtt {g}(\mathtt {t},0,0,\cdot \cdot \cdot ,0)\vert \Delta \mathtt {t}\\&\le \,2\mathtt {z}_a+\mathtt {z}_b+\mathtt {M}\sum _{\mathtt {j}=1}^{n}\upalpha _\mathtt {j}\sum _{\dot{\iota }=0}^{\mathtt {j}-1}\Bbbk ^{\dot{\iota }}\Vert \mathtt {z}\Vert +\mathtt {M}\mathtt {g}^\star \\&\le \,2\mathtt {z}_a+\mathtt {z}_b+\mathtt {M}\left[ \mathtt {L}\sum _{\mathtt {j}=1}^{n}\upalpha _\mathtt {j}\sum _{\dot{\iota }=0}^{\mathtt {j}-1}\Bbbk ^{\dot{\iota }}+\mathtt {g}^\star \right] \\&\le \,\mathtt {L}. \end{aligned} \end{aligned}$$

\(\square \)

Lemma 4

Suppose \((\mathcal {H}_1)\) and the following hold.

  • \((\mathcal {H}_3)\) \(\frac{\vert \mathtt {z}_b-\mathtt {z}_a\vert }{\upsigma ^2(b)-a}+\mathtt {N}\left[ \mathtt {g}^\star +\mathtt {L}\sum _{\mathtt {j}=1}^{n}\upalpha _\mathtt {j}\sum _{\dot{\iota }=0}^{\mathtt {j}-1}\Bbbk ^{\dot{\iota }}\right] \le \Bbbk .\)

Then \(\vert (\aleph \mathtt {z})(\mathtt {s}_1)-(\aleph \mathtt {z})(\mathtt {s}_2)\vert \le \Bbbk \vert \mathtt {s}_1-\mathtt {s}_2\vert \) for all \(\mathtt {s}_1,\mathtt {s}_2\in [a,\upsigma ^2(b)]_\mathbb {T}\) and \(\mathtt {z}\in \mathscr {B}(\mathtt {L},\Bbbk ).\)

Proof

Let \(\mathtt {s}_1,\mathtt {s}_2\in [a,\upsigma ^2(b)]_\mathbb {T}\) and \(\mathtt {z}\in \mathscr {B}(\mathtt {L},\Bbbk )\) with \(\mathtt {s}_1\le \mathtt {s}_2.\) Then

$$\begin{aligned} \begin{aligned} \vert (\aleph \mathtt {z})(\mathtt {s}_1)-(\aleph \mathtt {z})(\mathtt {s}_2)\vert&\le \,\frac{\vert \mathtt {z}_b-\mathtt {z}_a\vert }{\upsigma ^2(b)-a}\vert \mathtt {s}_1-\mathtt {s}_2\vert +\int _a^{\upsigma (b)}\vert \mathtt {G}(\mathtt {s}_1,\mathtt {t})\\&\quad -\mathtt {G}(\mathtt {s}_2,\mathtt {t})\vert \vert \mathtt {g}\big (\mathtt {t},\mathtt {z}(\mathtt {t}),\mathtt {z}^{[2]}(\mathtt {t}),\mathtt {z}^{[3]}(\mathtt {t}),\cdot \cdot \cdot ,\mathtt {z}^{[n]}(\mathtt {t})\big )\vert \Delta \mathtt {t}\\&\le \,\frac{\vert \mathtt {z}_b-\mathtt {z}_a\vert }{\upsigma ^2(b)-a}\vert \mathtt {s}_1-\mathtt {s}_2\vert +\int _a^{\upsigma (b)}\vert \mathtt {G}(\mathtt {s}_1,\mathtt {t})\\&\quad -\mathtt {G}(\mathtt {s}_2,\mathtt {t})\vert \Big \vert \mathtt {g}\big (\mathtt {t},\mathtt {z}(\mathtt {t}),\mathtt {z}^{[2]}(\mathtt {t}),\mathtt {z}^{[3]}(\mathtt {t}),\cdot \cdot \cdot ,\mathtt {z}^{[n]}(\mathtt {t})\big )\vert \Delta \mathtt {t}\\&\quad -\mathtt {g}(\mathtt {t},0,0,\cdot \cdot \cdot ,0)\Big \vert \Delta \mathtt {t}+\int _a^{\upsigma (b)}\vert \mathtt {G}(\mathtt {s}_1,\mathtt {t})\\&\quad -\mathtt {G}(\mathtt {s}_2,\mathtt {t})\vert \vert \mathtt {g}(\mathtt {t},0,0,\cdot \cdot \cdot ,0)\Big \vert \Delta \mathtt {t}\\&\le \,\frac{\vert \mathtt {z}_b-\mathtt {z}_a\vert }{\upsigma ^2(b)-a}\vert \mathtt {s}_1-\mathtt {s}_2\vert \\&\quad +\mathtt {N}\sum _{\mathtt {j}=1}^{n}\upalpha _\mathtt {j}\sum _{\dot{\iota }=0}^{\mathtt {j}-1}\Bbbk ^{\dot{\iota }}\Vert \mathtt {z}\Vert \vert \mathtt {s}_1-\mathtt {s}_2\vert +\mathtt {N}\mathtt {g}^\star \vert \mathtt {s}_1-\mathtt {s}_2\vert \\&\le \,\frac{\vert \mathtt {z}_b-\mathtt {z}_a\vert }{\upsigma ^2(b)-a}\vert \mathtt {s}_1-\mathtt {s}_2\vert \\&\quad +\mathtt {N}\left[ \mathtt {L}\sum _{\mathtt {j}=1}^{n}\upalpha _\mathtt {j}\sum _{\dot{\iota }=0}^{\mathtt {j}-1}\Bbbk ^{\dot{\iota }}+\mathtt {g}^\star \right] \vert \mathtt {s}_1-\mathtt {s}_2\vert \\&\le \,\Bbbk \vert \mathtt {s}_1-\mathtt {s}_2\vert . \end{aligned} \end{aligned}$$

\(\square \)

Lemma 5

Suppose \((\mathcal {H}_1)\)\((\mathcal {H}_3)\) hold. Then \(\aleph (\mathscr {B}(\mathtt {L},\Bbbk ))\subset \mathscr {B}(\mathtt {L},\Bbbk ).\)

Proof

It is clear from Lemmas 3 and 4 that \(\aleph \) maps \(\mathscr {B}(\mathtt {L},\Bbbk )\) into itself. \(\square \)

Theorem 1

Suppose \((\mathcal {H}_1)\)\((\mathcal {H}_3)\) hold. Then BPV (1)–(2) has a solution in \(\mathscr {B}(\mathtt {L},\Bbbk ).\)

Proof

From Lemmas 2 to 5, we see that all the conditions of Schauder’s fixed point theorem are satisfied on \(\mathscr {B}(\mathtt {L},\Bbbk ).\) thus there exists a fixed point \(\mathtt {z}^\star \) in \(\mathscr {B}(\mathtt {L},\Bbbk )\) such that \(\aleph \mathtt {z}^\star =\mathtt {z}^\star .\) Therefore, \(\mathtt {z}^\star \) is a solution of (1)–(2). This completes the proof. \(\square \)

Theorem 2

Suppose \((\mathcal {H}_1)\)-\((\mathcal {H}_3)\) and the following hold.

  • \((\mathcal {H}_4)\) \(\mathtt {M}\sum _{\mathtt {j}=1}^{n}\upalpha _\mathtt {j}\sum _{\dot{\iota }=0}^{\mathtt {j}-1}\Bbbk ^{\dot{\iota }}<1.\)

Then BPV (1)–(2) has a unique solution in \(\mathscr {B}(\mathtt {L},\Bbbk ).\)

Proof

Let \(\mathtt {z},\widehat{\mathtt {z}}\in \mathscr {B}(\mathtt {L},\Bbbk )\) and \(\mathtt {s}\in [a,\upsigma ^2(b)]_\mathbb {T}.\) Then by Lemma 2,

$$\begin{aligned} \begin{aligned} \Vert (\aleph \mathtt {z})(\mathtt {s})-(\aleph \widehat{\mathtt {z}})(\mathtt {s})\Vert \le \mathtt {M}\sum _{\mathtt {j}=1}^{n}\upalpha _\mathtt {j}\sum _{\dot{\iota }=0}^{\mathtt {j}-1}\Bbbk ^{\dot{\iota }}\Vert \mathtt {z}-\widehat{\mathtt {z}}\Vert \end{aligned} \end{aligned}$$

Therefore, by the contraction mapping principle \(\aleph \) has a unique fixed point in \(\mathscr {B}(\mathtt {L},\Bbbk ).\) This completes the proof.

3 Continuous dependence

In this section, we establish continuous dependence of the unique solution on \(\mathtt {g}.\)

Theorem 3

Suppose \((\mathcal {H}_1)\)\((\mathcal {H}_4)\) hold. Then unique solution of (1)–(2) obtained in Theorem 2 depends continuously on \(\mathtt {g}.\)

Proof

Let \(\mathtt {g}\) and \(\widehat{\mathtt {g}}\) be two given functions and consider the corresponding operators \(\aleph \) and \(\widehat{\aleph }\) defined by (8). Next by Theorem 2, there exist two unique functions \(\mathtt {z}(\mathtt {s})\) and \(\widehat{\mathtt {z}}(\mathtt {s})\) in \(\mathscr {B}(\mathtt {L},\Bbbk )\) such that \(\mathtt {z}=\aleph \mathtt {z}\) and \(\widehat{\mathtt {z}}=\widehat{\aleph }\widehat{\mathtt {z}}.\) Then,

$$\begin{aligned} \begin{aligned} \Vert \aleph \widehat{\mathtt {z}}-\widehat{\aleph }\widehat{\mathtt {z}}\Vert&\le \int _a^ {\upsigma (b)}\vert \mathtt {G}(\mathtt {s},\mathtt {t})\vert \Big \vert \mathtt {g}\big (\mathtt {t},\widehat{\mathtt {z}}(\mathtt {t}), \widehat{\mathtt {z}}^{[2]}(\mathtt {t}),\widehat{\mathtt {z}}^{[3]}(\mathtt {t}),\cdot \cdot \cdot ,\widehat{\mathtt {z}}^{[n]}(\mathtt {t})\big )\\&\quad -\widehat{\mathtt {g}}\big (\mathtt {t},\widehat{\mathtt {z}}(\mathtt {t}),\widehat{\mathtt {z}}^{[2]}(\mathtt {t}),\widehat{\mathtt {z}}^{[3]}(\mathtt {t}),\cdot \cdot \cdot ,\widehat{\mathtt {z}}^{[n]}(\mathtt {t})\big )\Big \vert \Delta \mathtt {t}\\&\le \int _a^{\upsigma (b)}\vert \mathtt {G}(\mathtt {s},\mathtt {t})\vert \Big [\Big \vert \mathtt {g}\big (\mathtt {t}, \widehat{\mathtt {z}}(\mathtt {t}),\widehat{\mathtt {z}}^{[2]}(\mathtt {t}),\widehat{\mathtt {z}}^{[3]}(\mathtt {t}), \cdot \cdot \cdot ,\widehat{\mathtt {z}}^{[n]}(\mathtt {t})\big )\\&\quad -\widehat{\mathtt {g}}\big (\mathtt {t},\mathtt {z}(\mathtt {t}),\mathtt {z}^{[2]}(\mathtt {t}),\mathtt {z}^{[3]}(\mathtt {t}), \cdot \cdot \cdot ,\mathtt {z}^{[n]}(\mathtt {t})\big )\Big \vert \\&\quad +\Big \vert \widehat{\mathtt {g}}\big (\mathtt {t},\mathtt {z}(\mathtt {t}),\mathtt {z}^{[2]}(\mathtt {t}),\mathtt {z}^{[3]} (\mathtt {t}),\cdot \cdot \cdot ,\mathtt {z}^{[n]}(\mathtt {t})\big )\\&\quad -\widehat{\mathtt {g}}\big (\mathtt {t},\widehat{\mathtt {z}} (\mathtt {t}),\widehat{\mathtt {z}}^{[2]}(\mathtt {t}),\widehat{\mathtt {z}}^{[3]}(\mathtt {t}),\cdot \cdot \cdot ,\widehat{\mathtt {z}}^{[n]} (\mathtt {t})\big )\Big \vert \Big ]\Delta \mathtt {t}\\&\le \int _a^{\upsigma (b)}\vert \mathtt {G}(\mathtt {s},\mathtt {t})\vert \Big [\Vert \mathtt {g}\\&\quad -\widehat{\mathtt {g}}\Vert +\sum _{\mathtt {j}=1}^{n}\upalpha _\mathtt {j}\sum _{\dot{\iota }=0}^{\mathtt {j}-1}\Bbbk ^{\dot{\iota }}\Vert \mathtt {z}-\widehat{\mathtt {z}}\Vert \Big ]\Delta \mathtt {t}\\&=\mathtt {M}\Big [\Vert \mathtt {g}-\widehat{\mathtt {g}}\Vert +\sum _{\mathtt {j}=1}^{n}\upalpha _\mathtt {j}\sum _{\dot{\iota }=0}^{\mathtt {j}-1}\Bbbk ^{\dot{\iota }}\Vert \mathtt {z}-\widehat{\mathtt {z}}\Vert \Big ]. \end{aligned} \end{aligned}$$

Therefore,

$$\begin{aligned} \begin{aligned} \Vert \mathtt {z}-\widehat{\mathtt {z}}\Vert&\le \Vert \aleph \mathtt {z}-\aleph \widehat{\mathtt {z}}\Vert +\Vert \aleph \widehat{\mathtt {z}}-\widehat{\aleph }\widehat{\mathtt {z}}\Vert \\&\le \mathtt {M}\sum _{\mathtt {j}=1}^{n}\upalpha _\mathtt {j}\sum _{\dot{\iota }=0}^{\mathtt {j}-1}\Bbbk ^{\dot{\iota }}\Vert \mathtt {z}-\widehat{\mathtt {z}}\Vert +\mathtt {M}\Big [\Vert \mathtt {g}-\widehat{\mathtt {g}}\Vert +\sum _{\mathtt {j}=1}^{n}\upalpha _\mathtt {j}\sum _{\dot{\iota }=0}^{\mathtt {j}-1}\Bbbk ^{\dot{\iota }}\Vert \mathtt {z}-\widehat{\mathtt {z}}\Vert \Big ]. \end{aligned} \end{aligned}$$

That is

$$\begin{aligned} \Vert \mathtt {z}-\widehat{\mathtt {z}}\Vert \le \mathtt {M}\left[ 1-2\mathtt {M}\sum _{\mathtt {j}=1}^{n}\upalpha _\mathtt {j}\sum _{\dot{\iota }=0}^{\mathtt {j}-1}\Bbbk ^{\dot{\iota }}\right] ^{-1}\Vert \mathtt {g}-\widehat{\mathtt {g}}\Vert . \end{aligned}$$

This completes the proof. \(\square \)

Example 1

Consider the time scale \(\mathbb {T}=\{10^m\vert m\in \mathbb {Z}\}\cup \{0\}\) and \(\mathtt {z}_a=1,\mathtt {z}_b=2,a=0,b=1\) in the (1)–(2). It follows from (6) that, for \(\mathtt {s}=\frac{1}{10^m},\,m=-1,0,1,\cdot \cdot \cdot ,\)

$$\begin{aligned} \begin{aligned} \max _{\mathtt {s}\in [0,100]_\mathbb {T}}\int _0^{10}\mathtt {G}(\mathtt {s},\mathtt {t})\Delta \mathtt {t}&=\max _{m} \left[ \lim _{k\rightarrow +\infty }\int _{\frac{1}{10^k}}^{\frac{1}{10^m}}10\mathtt {t}(10^2-\frac{1}{10^m})\Delta \mathtt {t}\right. \\&\left. \quad +\int _{\frac{1}{10^m}}^{10}\frac{1}{10^m}(10^2-10\mathtt {t})\Delta \mathtt {t}\right] \\&=\frac{10}{11}\max _{m}\left[ 101\times 10^{-2m}-10^{-3m}-10^{-2}\right] \\&=8181.818182. \end{aligned} \end{aligned}$$

So, \(\mathtt {M}=8181.818182\) and \(\mathtt {N}=400.\) Next, consider the function

$$\begin{aligned} \mathtt {g}(\mathtt {t},\mathtt {z}(\mathtt {t}),\mathtt {z}^{[2]}(\mathtt {t}),\mathtt {z}^{[3]}(\mathtt {t}))= & {} \cos (\mathtt {t})+\frac{\uppi }{154\times 10^3}\mathtt {z}(\mathtt {t})\\&+\frac{\uppi }{256\times 10^3}\sin (\mathtt {z}^{[2]}(\mathtt {t}))+\frac{\uppi }{323\times 10^3}\cos (\mathtt {z}^{[3]}(\mathtt {t})). \end{aligned}$$

Then

$$\begin{aligned}&\vert \mathtt {g}(\mathtt {t},\mathtt {z}_1,\mathtt {z}_2,\mathtt {z}_3)-\mathtt {g}(\mathtt {t},\widehat{\mathtt {z}}_1, \widehat{\mathtt {z}}_2,\widehat{\mathtt {z}}_3)\vert \le \upalpha _1\Vert \mathtt {z}_1-\widehat{\mathtt {z}}_1\Vert \\&\quad +\upalpha _2\Vert \mathtt {z}_2-\widehat{\mathtt {z}}_2\Vert +\upalpha _3\Vert \mathtt {z}_3-\widehat{\mathtt {z}}_3\Vert , \end{aligned}$$

where \(\upalpha _1=\frac{\uppi }{154\times 10^3},\upalpha _2=\frac{\uppi }{256\times 10^3},\upalpha _3=\frac{\uppi }{323\times 10^3}\) and

$$\begin{aligned} \mathtt {g}(\mathtt {t},0,0,0)=\cos (\mathtt {t})+\frac{\uppi }{323\times 10^3}\le 1.000009726:=\mathtt {g}^\star . \end{aligned}$$

Further, let \(\mathtt {L}=\frac{\uppi }{2.42\times 10^{-4}}\) and \(\Bbbk =\frac{\uppi }{4.95\times 10^{-3}}.\) Then

$$\begin{aligned} 2\vert \mathtt {z}_a\vert +\vert \mathtt {z}_b\vert +\mathtt {M}\left[ \mathtt {g}^\star +\mathtt {L}\sum _{\mathtt {j}=1}^{n}\upalpha _\mathtt {j}\sum _{\dot{\iota }=0}^{\mathtt {j}-1}\Bbbk ^{\dot{\iota }}\right]= & {} 12692.87935\le \mathtt {L},\\ \frac{\vert \mathtt {z}_b-\mathtt {z}_a\vert }{\upsigma ^2(b)-a}+\mathtt {N}\left[ \mathtt {g}^\star +\mathtt {L}\sum _{\mathtt {j}=1}^{n}\upalpha _\mathtt {j}\sum _{\dot{\iota }=0}^{\mathtt {j}-1}\Bbbk ^{\dot{\iota }}\right]= & {} 620.3552127\le \Bbbk \end{aligned}$$

and

$$\begin{aligned} \mathtt {M}\sum _{\mathtt {j}=1}^{n}\upalpha _\mathtt {j}\sum _{\dot{\iota }=0}^{\mathtt {j}-1}\Bbbk ^{\dot{\iota }}=0.3471772648<1. \end{aligned}$$

Thus, all assumptions \((\mathcal {H}_1)\)\((\mathcal {H}_4)\) hold. Therefore, the BVP

$$\begin{aligned} \left\{ \begin{aligned}&\mathtt {z}^{\Delta \Delta }(\mathtt {s})+\cos (\mathtt {s})+\frac{\uppi }{154\times 10^3}\mathtt {z}(\mathtt {s})\\&\quad +\frac{\uppi }{256\times 10^3}\sin (\mathtt {z}^{[2]}(\mathtt {s}))+\frac{\uppi }{323\times 10^3}\cos (\mathtt {z}^{[3]}(\mathtt {s}))=0,~\mathtt {s}\in [0,1]_\mathbb {T},\\&\mathtt {z}(0)=1, \mathtt {z}(\upsigma ^2(1))=2, \end{aligned}\right. \end{aligned}$$

has a unique solution in \(\mathscr {B}\left( \frac{\uppi }{2.42\times 10^{-4}},\frac{\uppi }{4.95\times 10^{-3}}\right) \) and depends continuously on the function \(\mathtt {g}.\)

4 Conclusion

Iterative differential equation, as a special type of functional differential equations, in which the deviating arguments depend on the state. Many researchers have concentrated on studying first order iterative functional differential equations by different approaches such as Picard’s successive approximation, fixed point theory and the technique of nonexpansive operators. But the literature related to the second and higher order is very less since the presence of the iterates increases the difficulty of studying them. This work gives a criteria for the existence, uniqueness and continuous dependence of solutions for nonlinear second order iterative functional boundary values with two-point boundary conditions on time scales. In the future, we study higher order iterative functional boundary value problems on time scales and fractional order iterative boundary value problems on time scales.