Contact of a node with the bottom could lead to a wearing force. This force is taken into account when there is a movement of the structure on the bottom. This force is horizontal and opposite to the motion. This wearing depends on the depth on which the node digs the bottom, on the bottom stiffness, and on the node speed displacement on the bottom.
6.3.1 Force Vector
As mentioned earlier (Sect. 6.2, p. 87), the vertical force on a node due to its contact (\(z<Z_b\)) to the bottom is:
$$\begin{aligned} F_c = B_k (Z_b - z) \end{aligned}$$
(6.5)
With:
\(F_c\): the vertical force on the node due to the contact to the bottom (N),
\(B_k\): the bottom stiffness (N/m),
\(Z_b\): the vertical position of the bottom (m),
\(z\): the vertical position of the node (m).
The drag force on the bottom has been modelled as a function of the displacement speed of the node on the bottom. Figure 6.1 shows this relation.
$$\begin{aligned} if \vert \mathbf{V } \vert < V_l\; \quad \vert \mathbf{F } \vert&= F_c B_f \frac{\vert \mathbf{V } \vert }{V_l} \end{aligned}$$
(6.6)
$$\begin{aligned} if \vert \mathbf{V } \vert \ge V_l\; \quad \vert \mathbf{F } \vert&= F_c B_f \end{aligned}$$
(6.7)
With:
$$\begin{aligned} \mathbf{V } = \begin{array}{| c} V_x \\ V_y \\ V_z \end{array} \end{aligned}$$
(6.8)
The components of speed are calculated as follows:
$$\begin{aligned} V_x&= \frac{x - x_p}{\varDelta t} \end{aligned}$$
(6.9)
$$\begin{aligned} V_y&= \frac{y - y_p}{\varDelta t} \end{aligned}$$
(6.10)
$$\begin{aligned} V_z&= \frac{z - z_p}{\varDelta t} \end{aligned}$$
(6.11)
\(V_x\) (\(V_y\), \(V_z\)): component of the speed of the node along the x (y, z) axis (m/s),
\(x\) (\(y\), \(z\)): coordinate of the node along the x (y, z) axis (m) calculated at time \({{t}}\),
\(x_p\) (\(y_p\), \(z_p\)): previous coordinate of the node along the x (y, z) axis (m) calculated at time \(t - \varDelta t\).
Two cases are defined: a high-speed case (\(\vert \mathbf{V } \vert \ge V_l\)) and a low-speed case (\(\vert \mathbf{V } \vert < V_l\)). The wearing force is calculated in the two cases such as there is continuity between the two cases (at \(\vert \mathbf{V } \vert = V_l\)).
6.3.1.1 High-Speed
In this case, \(\vert \mathbf{V } \vert \ge V_l\).
That means that the components of this force are the following:
$$\begin{aligned} F_x&= - F_c B_f \frac{V_x}{\vert \mathbf{V } \vert } \end{aligned}$$
(6.12)
$$\begin{aligned} F_y&= - F_c B_f \frac{V_y}{\vert \mathbf{V } \vert } \end{aligned}$$
(6.13)
$$\begin{aligned} F_z&= - F_c B_f \frac{V_z}{\vert \mathbf{V } \vert } \end{aligned}$$
(6.14)
6.3.1.2 Low-Speed
In this case, \(\vert \mathbf{V } \vert < V_l\).
That means that the components of this force are the following:
$$\begin{aligned} F_x&= - F_c B_f \frac{V_x}{V_l}\end{aligned}$$
(6.15)
$$\begin{aligned} F_y&= - F_c B_f \frac{V_y}{V_l}\end{aligned}$$
(6.16)
$$\begin{aligned} F_z&= - F_c B_f \frac{V_z}{V_l} \end{aligned}$$
(6.17)
6.3.2 Stiffness Matrix
6.3.2.1 High-Speed
$$\begin{aligned} \frac{\partial F_x}{\partial x}&= - \frac{F_c B_f}{\vert \mathbf V \vert ^2} \frac{\partial V_x}{\partial x} \left[ \vert \mathbf V \vert - \frac{V_x^2}{ \vert \mathbf V \vert } \right] \end{aligned}$$
(6.18)
$$\begin{aligned} \frac{\partial F_x}{\partial y}&= - \frac{F_c B_f}{\vert \mathbf V \vert ^2} \frac{\partial V_y}{\partial y} \left[ - \frac{V_x V_y}{ \vert \mathbf V \vert } \right] \end{aligned}$$
(6.19)
$$\begin{aligned} \frac{\partial F_x}{\partial z}&= B_k B_f \frac{V_x}{ \vert \mathbf V \vert } - \frac{F_c B_f}{\vert \mathbf V \vert ^2 } \left[ - \frac{V_x V_z}{ \vert \mathbf V \vert } \frac{\partial V_z}{\partial z}\right] \end{aligned}$$
(6.20)
$$\begin{aligned} \frac{\partial F_y}{\partial x}&= \frac{F_c B_f}{\vert \mathbf V \vert ^2} \left[ \frac{ V_x V_y}{ \vert \mathbf V \vert } \frac{\partial V_x}{\partial x} \right] \end{aligned}$$
(6.21)
$$\begin{aligned} \frac{\partial F_y}{\partial y}&= - \frac{F_c B_f}{\vert \mathbf V \vert ^2} \frac{\partial V_y}{\partial y} \left[ \vert \mathbf V \vert - \frac{V_y^2}{ \vert \mathbf V \vert } \right] \end{aligned}$$
(6.22)
$$\begin{aligned} \frac{\partial F_y}{\partial z}&= B_k B_f \frac{V_y}{\vert \mathbf V \vert } - \frac{F_c B_f}{\vert \mathbf V \vert ^2} \left[ -\frac{V_x V_z}{\vert \mathbf V \vert } \frac{\partial V_z}{\partial z} \right] \end{aligned}$$
(6.23)
$$\begin{aligned} \frac{\partial F_z}{\partial x}&= \frac{F_c B_f}{\vert \mathbf V \vert ^2} \left[ \frac{V_x V_z}{\vert \mathbf V \vert } \frac{\partial V_x}{\partial x}\right] \end{aligned}$$
(6.24)
$$\begin{aligned} \frac{\partial F_z}{\partial y}&= \frac{F_c B_f}{\vert \mathbf V \vert ^2} \left[ \frac{V_y V_z}{\vert \mathbf V \vert } \frac{\partial V_y}{\partial y}\right] \end{aligned}$$
(6.25)
$$\begin{aligned} \frac{\partial F_z}{\partial z}&= B_k B_f \frac{V_z}{\vert \mathbf V \vert } - \frac{F_c B_f}{\vert \mathbf V \vert ^2} \left[ \frac{\partial V_z}{\partial z} \vert \mathbf V \vert -\frac{V_z^2}{\vert \mathbf V \vert } \frac{\partial V_z}{\partial z}\right] \end{aligned}$$
(6.26)
With:
$$\begin{aligned} \frac{\partial V_x}{\partial x}&= \frac{1}{\varDelta t}\end{aligned}$$
(6.27)
$$\begin{aligned} \frac{\partial V_y}{\partial y}&= \frac{1}{\varDelta t}\end{aligned}$$
(6.28)
$$\begin{aligned} \frac{\partial V_z}{\partial z}&= \frac{1}{\varDelta t} \end{aligned}$$
(6.29)
The stiffness matrix becomes:
$$\begin{aligned} K= -\frac{B_f F_c}{\vert \mathbf{V } \vert ^2 \varDelta t} \left( \begin{array}{ccc} \frac{V_x^2}{\vert \mathbf{V } \vert } - \vert \mathbf{V } \vert &{} \frac{V_x V_y}{\vert \mathbf{V } \vert } &{} \frac{V_x V_z}{\vert \mathbf{V } \vert } \\ \frac{V_x V_y}{\vert \mathbf{V } \vert } &{} \frac{V_y^2}{\vert \mathbf{V } \vert } - \vert \mathbf{V } \vert &{} \frac{V_y V_z}{\vert \mathbf{V } \vert } \\ \frac{V_x V_z}{\vert \mathbf{V } \vert } &{} \frac{V_y V_z}{\vert \mathbf{V } \vert } &{} \frac{V_z^2}{\vert \mathbf{V } \vert } - \vert \mathbf{V } \vert \\ \end{array} \right) -\frac{B_f B_k}{\vert \mathbf{V } \vert } \left( \begin{array}{ccc} 0 &{} 0 &{} V_x \\ 0 &{} 0 &{} V_y \\ 0 &{} 0 &{} V_z \\ \end{array} \right) \end{aligned}$$
(6.30)
6.3.2.2 Low-Speed
$$\begin{aligned} \frac{\partial F_x}{\partial x}&= -\frac{F_c B_f}{V_l} \frac{\partial V_x}{\partial x}\end{aligned}$$
(6.31)
$$\begin{aligned} \frac{\partial F_x}{\partial y}&= 0\end{aligned}$$
(6.32)
$$\begin{aligned} \frac{\partial F_x}{\partial z}&= B_k B_f \frac{V_x}{V_l}\end{aligned}$$
(6.33)
$$\begin{aligned} \frac{\partial F_y}{\partial x}&= 0\end{aligned}$$
(6.34)
$$\begin{aligned} \frac{\partial F_y}{\partial y}&= -\frac{F_c B_f}{V_l} \frac{\partial V_y}{\partial y}\end{aligned}$$
(6.35)
$$\begin{aligned} \frac{\partial F_y}{\partial z}&= B_k B_f \frac{V_y}{V_l}\end{aligned}$$
(6.36)
$$\begin{aligned} \frac{\partial F_z}{\partial x}&= 0\end{aligned}$$
(6.37)
$$\begin{aligned} \frac{\partial F_z}{\partial y}&= 0\end{aligned}$$
(6.38)
$$\begin{aligned} \frac{\partial F_z}{\partial z}&= B_k B_f \frac{V_z}{V_l} - \frac{F_c B_f}{V_l} \frac{\partial V_z}{\partial z} \end{aligned}$$
(6.39)
The stiffness matrix becomes:
$$\begin{aligned} K= -\frac{B_f}{V_l} \left( \begin{array}{ccc} \frac{F_c}{\varDelta t} &{} 0 &{} -B_k V_x \\ 0 &{} \frac{F_c}{\varDelta t} &{} -B_k V_y \\ 0 &{} 0 &{} \frac{F_c}{\varDelta t} - B_k V_z \\ \end{array} \right) \end{aligned}$$
(6.40)