As an application of results obtained in Chap. 3, we will study conditions for almost periodicity of solutions of the linear differential equation \(x'(t)=Ax(t)+f(t),\;t\in \mathbb R\) and the associated homogeneous equation in locally convex spaces. We will start with the case of a bounded linear operator A and then study the general case of a (eventually unbounded) linear operator A which generates an equicontinuous C 0-semigroup of linear operators.

1 Linear Equations

Definition 11.1

A Fréchet space E is said to be perfect if it satisfies the following property:

(F) Every function \(f:\mathbb R\to E\) with a bounded range \(\{f(t):\;\;t\in \mathbb R\}\) and f′(t) almost periodic is necessarily almost periodic.

Example 11.2

Denote by s the linear space of all real numbers \(s=\{x=(x_n):\;\;x_n\in \mathbb R,\;\;n=1,2,\ldots \}\). For each n, define

$$\displaystyle \begin{aligned} p_n(x):=|x_n|,\;\;x\in s. \end{aligned}$$

Obviously p n is a seminorm defined on s. Define

$$\displaystyle \begin{aligned}q_n:=p_1\vee p_2\vee\ldots\vee p_n,\;\;n=1,2,\ldots\end{aligned}$$

We have q n ≤ q n+1, n = 1, 2, … The space s considered with the family of seminorms (q n) is a Fréchet space. Moreover, it can be proved (see [1], 17.7, p. 210) that each closed and bounded subset of s is compact. Thus, in particular, s is a Banach space. Moreover, in view of Theorem 8.12, s is perfect.

1.1 The Homogeneous Equation x′ = Ax

Consider in a complete Hausdorff locally convex space E the equation

$$\displaystyle \begin{aligned} x'(t)=Ax(t),\;t\in\mathbb R. \end{aligned} $$
(1.1)

Theorem 11.3 ([51])

Let E be a perfect Fréchet space. Assume that

  1. (i)

    A is a compact linear operator on E;

  2. (ii)

    {A k : k = 1, 2, …} is equicontinuous;

  3. (iii)

    for every seminorm p, there exists a seminorm q such that

    $$\displaystyle \begin{aligned}p(e^{tA}x)\leq q(x),\;\;\mathit{\mbox{for every}}\;t\in \mathbb R,\;x\in E.\end{aligned}$$

    Then, the unique solution of Eq.( 1.48 ) is almost periodic in E.

Proof

Let x(t) = e tA x 0 be the unique solution of Eq. (1.1). Then, by (iii), it is bounded. Since E is a perfect Fréchet space, it suffices to prove that x′(t) is almost periodic (cf. Property (F) above).

Now, assumption (i) implies that the set \(\{x'(t):\;\in \mathbb R\}\) is also relatively compact in E.

Let \((s^{\prime }_n)\) be an arbitrary sequence of real numbers; then, we can extract a subsequence (s n) such that (x′(s n)) is convergent and thus is a Cauchy sequence in E.

But we have

$$\displaystyle \begin{aligned}\begin{array}{rlll} x'(t+s_n)&=&Ax(t+s_n)\\ &=&A e^{(t+s_n)A}x_0\\ &=&Ae^{tA}e^{s_nA}x_0\\ &=&Ae^{tA}x(s_n)\\ &=&e^{tA}Ax(s_n)\\ &=&e^{tA}x'(s_n) \end{array} \end{aligned}$$

for every n = 1, 2, … and every \(t\in \mathbb R\).

If p is a seminorm on E, then there exists a seminorm q on E such that

$$\displaystyle \begin{aligned}\begin{array}{rllll} p(x'(t+s_n)-x'(t+s_m))&=&p(e^{tA}(x'(s_n)-x'(s_m)))\\ &\leq& q(x'(s_n)-x'(s_m)) \end{array} \end{aligned}$$

for every n, m and every \(t\in \mathbb R\).

It follows that (x′(t + s n)) is uniformly Cauchy in t; therefore, it is uniformly convergent in t.

We conclude by Bochner’s criterion that x′(t) is almost periodic. This completes the proof. □

1.2 The Inhomogeneous Case

Now, let us consider in a perfect Fréchet space E the inhomogeneous equation:

$$\displaystyle \begin{aligned} x'(t)=Ax(t)+f(t),\;\;t\in\mathbb R, \end{aligned} $$
(1.2)

with the following assumptions:

  1. (H1)

    A is a compact linear operator on E;

  2. (H2)

    {A k; k = 1, 2, …} is equicontinuous;

  3. (H3)

    for every seminorm p n, there exists a seminorm q n such that

    $$\displaystyle \begin{aligned}p_n(e^{tA}x)\leq q_n(x),\;\;\mbox{for every}\;t\in\mathbb R,\;x\in E;\end{aligned}$$
  4. (H4)

    f ∈ AP(E) and for each \(p_n\in \mathcal {P}\), there exists a function \(\psi _{p_{n}}:\mathbb R\to \mathbb R^+\) with

    $$\displaystyle \begin{aligned}p_n(f(s))\leq \psi_{p_{n}}(s)\;\;\mbox{and}\;\; \int_{-\infty}^{\infty}\psi_{p_{n}}(s)ds<\infty.\end{aligned}$$

    Now, let us state and prove the following.

Theorem 11.4 ([16])

Under assumptions (H1)–(H4), every solution of Eq.(1.2) is almost periodic in E.

Proof

By Theorem 11.3, the function e tA x(0) ∈ AP(E).

Now, let \(F(t):=\int _{0}^{t}e^{(t-s)A}f(s)ds\). It is also immediate that s → e sA f(s) is in AP(E) based on Theorem 8.26. In view of assumptions (H5) and (H8), F(t) is bounded over \(\mathbb R\). We then deduce that \(\int _{0}^{t}e^{-sA}f(s)ds\in AP(E)\) since E is a perfect Fréchet space. But this last integral is equal to e tA F(t). Applying again Theorem 8.26, we obtain e tA(e tA F(t)) = F(t) is almost periodic. The proof is now complete. □

Let us now consider a Fréchet space in which property (F) may not hold.

Theorem 11.5 ([51, 55])

Let E be a Fréchet space (not necessarily perfect), and assume that assumptions (i)–(iii) of Theorem 11.3 are satisfied. Assume also that the range \(\mathcal {R}(A)\) of the operator A is dense in E.

Then, every solution of Eq.(1.1) is almost periodic.

Proof

Let us observe that the first part of the proof of Theorem 11.3 tells us that if x(t) = e tA x 0 is a solution of Eq. (1.48) with x 0 ∈ D(A) the domain of A, then x′(t) will be almost periodic. □

Lemma 11.6

Every solution of Eq.( 1.48 ) with initial data in \(\mathcal {R}(A)\) , the range of A, is almost periodic.

Proof

Let \(a\in \mathcal {R}(A)\) and consider the unique solution y(t) with y(0) = a. There exists x 0 ∈ D(A) such that Ax 0 = a. We have

$$\displaystyle \begin{aligned}y(t)=e^{tA}a=e^{tA}Ax_0=Ae^{tA}x_0=Ax(t)=x'(t),\end{aligned}$$

where x(t) = e tA x 0. Therefore, x′(t), and consequently y(t), is almost periodic. □

Proof (of Theorem 11.5 (continued))

Consider the solution x(t) of Eq. (1.48) with x(0) ∈ E. Since \(\mathcal {R}(A)\) is dense in E, there exists a sequence (a n) in \(\mathcal {R}(A)\) such that

$$\displaystyle \begin{aligned}\displaystyle\lim_{n\to\infty}a_n=x(0).\end{aligned}$$

Consider a sequence of solutions (y n(t)) with y n(0) = a n, n = 1, 2, … By the above, each y n(t) is almost periodic. □

Now, to prove almost periodicity of x(t), it suffices to prove that (y n(t)) converges to x(t) uniformly in \(t\in \mathbb R\). We have

$$\displaystyle \begin{aligned}x(t)=e^{tA}x(0),\;\;y_n(t)=e^{tA}a_n.\end{aligned}$$

So, given a seminorm p, there exists a seminorm q by (iii) such that

$$\displaystyle \begin{aligned}p(y_n(t)-x(t))=p(e^{tA}(a_n-x(0)))\leq q(a_n-x(0))\end{aligned}$$

for every n = 1, 2, … and every \(t\in \mathbb R\). The conclusion follows immediately.

Bibliographical Notes

The contributions in this chapter are due to D. Bugajewski and G.M. N’Guérékata [16, 55].