Abstract
The edge-connectivity of a connected hypergraph H is the minimum number of edges (named as edge-cut) whose removal makes H disconnected. It is known that the edge-connectivity of a hypergraph is bounded above by its minimum degree. H is super edge-connected, if every edge-cut consists of edges incident with a vertex of minimum degree. A hypergraph H is linear if any two edges of H share at most one vertex. We call H uniform if all edges of H have the same cardinality. Sufficient conditions for equality of edge-connectivity and minimum degree of graphs and super edge-connected graphs are known. In this paper, we present a generalization of some of these sufficient conditions to linear and/or uniform hypergraphs.
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1 Introduction
As one of the classical parameters that indicate how reliable a graph G is, the edge-connectivity \(\lambda (G)\), defined as the minimum number of edges whose removal renders G disconnected, has attracted much attention in recent years. In 1932, Whitney [18] established one of the basic foundations of edge-connectivity for graphs: the edge-connectivity \(\lambda (G)\) of a connected graph G is bounded above by the minimum degree \(\delta (G)\). Thus, in order to study reliability and fault tolerance of graphs, sufficient conditions for graphs satisfying \(\lambda (G) = \delta (G)\) (so called maximally edge-connected) are of great interest. For other results the reader is referred to, for example, [5] and the survey [12].
Hypergraphs are a natural generalization of graphs in which “edges” may consist of more than 2 vertices. More precisely, a hypergraph \(H = (V, E)\) consists of a set V and a collection E of non-empty subsets of V. The elements of V are called vertices and the elements of E are called hyperedges, or simply edges. We define the order and size of H by \(n = |V(H)|\) and \(m = |E(H)|\), respectively. Unless specified otherwise, we consider only simple hypergraphs, i.e., hypergraphs whose edges are distinct. An r-uniform hypergraph H is a hypergraph such that all edges of H have cardinality r. We use \(K_n^{r}\) to denote the complete r-uniform hypergraph of order n, i.e., the hypergraph on n vertices whose edge set consists of all possible r-subsets of the vertex set. A hypergraph is called linear if any two edges of the hypergraph share at most one vertex. Obviously, every (simple) graph is a (linear) 2-uniform hypergraph.
For \(v, w \in V\), v and w are said to be adjacent, if there exists an edge \(e \in E\) such that \(\{v, w\} \subseteq e\). A vertex v and an edge e are said to be incident if \(v \in e\). The degree of a vertex v, denoted by \(d_H(v)\), is the number of edges which are incident to v. The minimum degree and maximum degree among the vertices of H are denoted by \(\delta (H)\) and \(\Delta (H)\), respectively. The neighborhood of a vertex v, denoted by \(N_H(v)\), is the set of all vertices different from v that are adjacent to v. If H is clear from the contest, we denote \(d_H(v)\) and \(N_H(v)\) by d(v) and N(v), respectively. For \(X \subseteq V\), use H[X] to denote the subgraph of H induced by X.
A walk in a hypergraph H is a finite alternating sequence \(W = (v_{0}, e_{1}, v_{1}, e_{2}, ... , e_{k}, v_{k})\), where \(v_{i} \in V\) for \(i \in \{0, 1, ... , k\}\) and \(e_{j} \in E\) such that \(\{v_{j - 1}, v_{j}\} \in e_{j}\) for \(j \in \{1, 2, ... , k\}\). A walk W is a path if all the vertices \(v_{i}\) for \(i \in \{0, 1, ..., k\}\) and all the edges \(e_{j}\) for \(j \in \{1, 2, ... , k\}\) in W are distinct. The length of a path, is the number of edges that it contains. We define the distance between two vertices u and v, denoted by \(d_H(u, v)\), as the length of a shortest path between u and v. A hypergraph is connected, if there is a walk between any pair of its vertices, otherwise it is disconnected. The diameter D(H) of a connected hypergraph H is defined by \(D(H) = max_{u, v \in V(H)}d_H(u, v)\).
We can extend the concept of edge-connectivity from graph theory to hypergraphs in a natural way in which the concept can be generalized. For a subset \(S \subseteq E(H)\), we define \(H - S\) to be the hypergraph obtained from H by deleting the edges in S without affecting the rest of the hypergraph. When \(H - S\) is disconnected, we say that S is an edge-cut. The minimum cardinality of an edge-cut in a connected hypergraph H is called its edge-connectivity, denoted by \(\lambda (H).\)
There has been several papers investigating the connectivity of the hypergraphs. In [19], Zykov presented a Menger-type theorem for hypergraphs. Edge augmentation of hypergraphs are studied in the literature (see e.g. [1, 2, 4]). Gu and Lai [10] gave necessary and sufficient conditions for an r-uniform hypergraphic sequence to have a k-edge-connected relazation. Jami et al. [13] provided a generalization of a result on edge-connectivity of permutation graphs for hypergraphs. In [6], Dankelmann and Meierling observed that \(\lambda (H) \le \delta (H)\) for general hypergraphs, and generalized some well-known sufficient conditions for graphs G satisfying \(\lambda (G) = \delta (G)\) to hypergraphs. In [7], the authors investigated vertex-connectivity of hypergraphs. For a subset \(X \subset V(H)\), \(H - X\) denotes the hypergraph obtained by removing the vertices X from H and removing all the edges that intersect X. The vertex-connectivity \(\kappa (H)\), is defined as the minimum cardinality of such X whose removal makes G disconnected. In [7], they also defined another vertex-connectivity for hypergraphs, and considered the complexity of the two kinds of vertex-connectivity for hypergraphs. The following result in [7] provided a generalization of a result of Whitney [18] on connectivity of graphs to hypergraphs.
Theorem 1.1
([7]). Let H be a hypergraph with at least two vertices. Then \(\kappa (H) \le \lambda (H) \le \delta (H)\).
Thus, we call a hypergraph H satisfying \(\lambda (H) = \delta (H)\) (resp. \(\kappa (H) = \delta (H)\)) maximally edge-connected (resp. maximally vertex-connected). If, furthermore, every minimum edge-cut consists of edges incident with one vertex, then H is said to be super edge-connected, or simply, super-\(\lambda\). Our main work is to investigate how some sufficient conditions for graphs to be maximally edge-connected or super-\(\lambda\) can be generalized to uniform and/or linear hypergraphs. In Section 2, we present results that will be useful in our arguments. In Section 3, two kinds of degree conditions for equality of edge-connectivity and minimum degree for graphs are generalized to uniform linear hypergraphs. In Section 4, we generalize a sufficient condition for maximally edge-connected graphs depending on the order, the maximum degree and the minimum degree as well as on the diameter, to uniform linear hypergraphs. In Section 5, we generalize a sufficient condition for maximally edge-connected graphs and super-\(\lambda\) graphs depending on the size, the order, the minimum degree and a parameter (as defined in Section 5) to uniform hypergraphs.
2 Preliminary lemmas
In this section, we will list or prove some lemmas which will be used in our later proofs.
In a connected hypergraph \(H = (V, E)\), let \(S \subseteq E\) be a minimum edge-cut of H and \(H_{1}\) be a component of \(H - S\). A vertex v of \(H_{1}\) is internal if v is not incident with any edge of S; otherwise, v will be external. In 1981, Goldsmith confirmed a very useful lemma in [9] when he studied the n-th order edge-connectivity of graphs. Now we present the special case of his lemma as follows.
Lemma 2.1
([9]). Let S be a minimum edge-cut of a graph G. If \(\lambda (G) < \delta (G)\), then each component of \(G - S\) contains at least two internal vertices.
And we will give a similar result with Lemma 2.1 for uniform linear hypergraphs.
Lemma 2.2
Let H be an r-uniform linear hypergraph and S be a minimum edge-cut of H. If \(\lambda (H) < \delta (H)\), then each component of \(H - S\) contains at least one internal vertex.
Proof
Let \(H_{1}\) be a component of \(H - S\) and x be an external vertex of \(H_{1}\). Set \(E_{1} = \{ e \in E \mid x \in e\) and \(e \in E(H_{1})\}\), and \(E_{2} = \{ e \in E \mid x \in e\) and \(e \in S\}\). Obviously, \(E_{2} \ne \varnothing\). If \(E_{1} = \varnothing\), then \(\delta (H) > \lambda (H) = |S| \ge |E_{2}| = d(x) \ge \delta (H)\), a contradiction. Thus, \(E_{1} \ne \varnothing\). It follows that \(|E_{1}| + |E_{2}| = d(x) \ge \delta (H) > \lambda (H) = |S| = |E_{2}| + |S - E_{2}|\), which implies that \(|E_{1}| > |S - E_{2}|\). Since H is linear and each edge of \(S - E_{2}\) is incident with at most \(r - 1\) vertices in \(V(H_{1})\), we have
and \((\bigcup \limits _{e \in E_{1}} (e - \{x\})) \cap (\bigcup \limits _{e \in E_{2}} (e - \{x\})) = \varnothing\), which implies that there exists at least one vertex \(w \in N(x) \cap (\bigcup \limits _{e \in E_{1}} e)\) that is not covered by any edge of S, i.e., w is an internal vertex of \(H_{1}\). \(\square\)
Our lemma implies the following two results of [6] for linear r-uniform hypergraphs to be maximally edge-connected.
Theorem 2.3
([6]). Let H be an r-uniform linear hypergraph with \(D(H) \le 2\). Then \(\lambda (H) = \delta (H)\).
Proof
Let S be a minimum edge-cut of H. The distance condition implies that there exists at least one component of \(H - S\) that contains no internal vertex. Then by Lemma 2.2, we have \(\lambda (H) \ge \delta (H)\) and the result holds. \(\square\)
If \(\lambda (H) < \delta (H)\), then by Lemma 2.2, each component of \(H - S\) contains at least one internal vertex w. It follows that each component of \(H - S\) contains at least \(1 + (r - 1)\delta (H)\) vertices (\(N(w) \cup \{w\} \subseteq V(H_{1})\) and thus \(|V(H_{1})| \ge 1 + (r - 1)d(w) \ge 1 + (r - 1)\delta (H)\)). Hence, \(|V(H)| \ge 2 + 2(r - 1)\delta (H)\), and we obtain the following condition for linear uniform hypergraphs to be maximally edge-connected.
Theorem 2.4
([6]). Let H be an r-uniform linear hypergraph of order n. If \(n \le 1 + 2(r - 1)\delta (H)\), then \(\lambda (H) = \delta (H)\).
The special case \(r = 2\) is the classical result as the following.
Corollary 2.5
Let G be a connected graph of order n. Then \(\lambda (G) = \delta (G)\), if
3 Degree conditions
We now work towards a generalization of some degree conditions for equality of edge-connectivity and minimum degree for graphs to linear uniform hypergraphs. We point out here that we present the same generalizations as that of [16], but use a different method from [16]. For the sake of completeness, we also give the complete proof in our paper. In 1974, Lesniak [14] proved the following strengthening result of Corollary 2.5 (1) for graphs.
Theorem 3.1
([14]). If G is a graph of order n with \(d(u) + d(v) \ge n - 1\) for all distinct non-adjacent vertices u and v, then \(\lambda (G) = \delta (G)\).
Below we present a generalization of the above result for r-uniform linear hypergraphs.
Theorem 3.2
Let H be an r-uniform linear hypergraph of order n. If \(d(u) + d(v) \ge \lceil \frac{n - 1}{r - 1}\rceil\) for all distinct non-adjacent vertices u and v, then \(\lambda (H) = \delta (H)\).
Proof
Let \(H = (V, E)\) and let \(S \subseteq E\) be a minimum edge-cut of H. Then \(H - S\) consists of two parts \(H_{1}\) and \(H_{2}\) such that there are no edges between \(H_{1}\) and \(H_{2}\). Denote the vertex set of \(H_{i}\) by \(V_{i}\) for \(i = 1, 2\). We claim that there exists no internal vertex in \(H_{1}\) or \(H_{2}\). Suppose, on the contrary, that there exist internal vertices \(x_{i} \in V_{i}\) for \(i = 1, 2\). Then \(x_{1}\) and \(x_{2}\) are non-adjacent and \(d(x_{1}) + d(x_{2}) \le \lfloor \frac{|V_{1}| - 1}{r - 1}\rfloor + \lfloor \frac{|V_{2}| - 1}{r - 1}\rfloor \le \frac{n - 2}{r - 1} < \frac{n - 1}{r - 1}\), contradict to the hypothesis. Thus, by Lemma 2.2, we have that \(\lambda (H) = \delta (H)\). \(\square\)
Note that Theorem 3.1 is a special case of Theorem 3.2 when \(r = 2\). Fig. 1 shows that Theorem 3.2 is in a sense a best possible result, since \(d(u) + d(v) \ge \lceil \frac{n - 1}{r - 1}\rceil - 1\) for all pairs of non-adjacent vertices of \(H_1\) and \(H_1\) is not maximally edge-connected.
Theorem 3.3
Let H be an r-uniform linear hypergraph of order n. If for each edge e there exist at least \(r - 1\) vertices incident with e such that each degree is at least \(\lceil \frac{\lfloor \frac{n}{2} \rfloor }{r - 1}\rceil\), then \(\lambda (H) = \delta (H)\).
Proof
Let S be a minimum edge-cut of H and let \(H_{1}\) be a component of \(H - S\) with the minimum cardinality. Then \(|V(H_{1})| \le \lfloor \frac{n}{2} \rfloor\). If \(|V(H_{1})| = 1\), then the result follows. In the following, we assume that \(|V(H_{1})| \ge 2\). Let \(v \in V(H_{1})\) such that \(d(v) = min \{d(x) \mid x \in V(H_{1})\}\). Set \(E_{1} = \{ e \in E \mid v \in e\) and \(e \in E(H_{1})\}\), and \(E_{2} = \{ e \in E \mid v \in e\) and \(e \in S\}\). We consider the following two cases.
- Case 1::
-
\(d(v) \ge \lceil \frac{\lfloor \frac{n}{2} \rfloor }{r - 1}\rceil\) It follows that \(d(x) \ge \lceil \frac{\lfloor \frac{n}{2} \rfloor }{r - 1}\rceil\) for all \(x \in V(H_{1})\). Since \(d_{H_{1}}(x) \le \lfloor \frac{|V(H_{1})| - 1}{r - 1}\rfloor \le \lfloor \frac{\lfloor \frac{n}{2} \rfloor - 1}{r - 1}\rfloor\), we see that \(H_{1}\) contains no internal vertices. And by Lemma 2.2, we have \(\lambda (H) = \delta (H)\).
- Case 2::
-
\(d(v) < \lceil \frac{\lfloor \frac{n}{2} \rfloor }{r - 1}\rceil\)
If \(E_{1} = \varnothing\), then \(\delta (H) \le d(v) = |E_{2}| \le |S| = \lambda (H)\), and the result follows. Now, we assume that \(E_{1} \ne \varnothing\). In this condition, by our hypothesis, we have \(d(x) \ge \lceil \frac{\lfloor \frac{n}{2} \rfloor }{r - 1}\rceil\) for any \(x \in X\), where \(X = \bigcup \limits _{e \in E_{1}} (e - \{v\})\), which implies that each vertex x in X is an external vertex. Set \(Y = \{e_{u} \in E \ | \ u \in e_{u} \in S\) and \(u \in X\}\), then \(Y \cap E_{2} = \varnothing\) since H is linear. It follows that \((r -1)|E_{1}| = |X| = |(\bigcup \limits _{e \in Y} e) \cap X| \le (r - 1)|Y|\) and we have \(|E_{1}| \le |Y|\). Thus, \(\delta (H) \le d(v) = |E_{1}| + |E_{2}| \le |Y| + |E_{2}| \le |S| = \lambda (H) \le \delta (H)\), and the proof is complete. \(\square\)
It is easy to check that \(H_1\) in Fig. 1 is a regular hypergraph and Fig. 1 can also show that Theorem 3.3 is a best possible result in a sense. Now, we give an irregular hypergraph \(H_2\) (see Fig. 2), which is not maximally edge-connected, and there exist at least \(r - 1\) vertices incident with each edge such that each degree is at least \(\lceil \frac{\lfloor \frac{n}{2} \rfloor }{r - 1}\rceil - 1\).
When \(r = 2\), as a special case of Theorem 3.3, we can get the following degree condition for maximally edge-connected graphs.
Theorem 3.4
([11]). Let G be a connected graph. If for each edge e there exists at least one vertex v incident with e such that \(d(v) \ge \lfloor \frac{n}{2}\rfloor\), then \(\lambda (G) = \delta (G)\).
4 A sufficient condition about order
In this section, we present a generalization of the following result by Esfahanian.
Theorem 4.1
([8]). Let G be a graph with maximum degree \(\Delta \ge 3\), minimum degree \(\delta\), diameter D and order n. Then \(\lambda (G) = \delta (G)\), when
Now, consider an r-uniform linear hypergraph \(H = (V, E)\) with maximum degree \(\Delta (H) = \Delta\) and let \(X_{0} \subset V\) with \(X_{0} = \{x_1, x_2, ..., x_p\}\), where \(|X_{0}| = p\). Denote by \(\overline{X_{0}} = V \backslash X_0\). For each \(x_{i} \in X_{0}\), let \(X_{i} = N(x_{i}) \cap \overline{X_{0}}\), where \(i \in \{1, 2, ..., p\}\). For a vertex \(x \in \overline{X_{0}}\), \(d(x, X_{0})\) denotes min\(\{d(x, u) \mid u \in X_{0}\}\). Define \(k = max\{d(x, X_{0}) \mid x \in \overline{X_{0}}\}\). We claim that n, the order of H, is bounded by:
which is equivalent to
To see the validity of the above claim, observe that for each vertex \(u \in \overline{X_{0}}\), there exists a vertex \(x_{j} \in X_{0}\) such that \(d(u, x_j) \le k\). And, in the right-hand side of the inequality (1), for each \(x_i \in X_{0}\), the maximum number of vertices in \(\overline{X_{0}}\), which are at distance less than or equal to k from \(x_{i}\), is computed.
Using the discussion above we now compute the upper-bound on n, as a function of other hypergraph parameters.
Theorem 4.2
Let n, \(\lambda\), \(\delta\), \(\Delta\) and D respectively be the order, the edge-connectivity, the minimum degree, the maximun degree and the diameter of an r-uniform linear hypergraph \(H = (V, E)\). If \(\lambda < \delta\) and \(\Delta > 2\), then
Proof
Let \(S \subseteq E\) be a minimum edge-cut of H. We can partition V into two disjoint non-empty sets Y and \({\overline{Y}}\) such that \(H - S\) contains no edges between Y and \({\overline{Y}}\). Let \(Y_{0}\) and \(\overline{Y_{0}}\) be the sets of external vertices respectively in Y and \({\overline{Y}}\). Let \(D_{Y} = max\{d(y, Y_{0}) \mid y \in Y\}\), and \(D_{{\overline{Y}}} = max\{d(y^{'}, \overline{Y_{0}}) \mid y^{'} \in {\overline{Y}}\}\). Since \(\lambda < \delta\), then \(D_{Y} \ge 1\) and \(D_{{\overline{Y}}} \ge 1\) by Lemma 2.2. And it is easy to see that \(D_{Y} + D_{{\overline{Y}}} + 1 \le D\).
Set \(Y_{0} = \{x_1, x_2, ..., x_p \}\), and \(\overline{Y_0} = \{x_1^{'}, x_2^{'}, ..., x_q^{'}\}\) where \(p = |Y_{0}|\) and \(q = |\overline{Y_0}|\). Let \(X_{i} = N(x_{i}) \cap (Y - Y_0)\) and \(X_{i}^{'} = N(x_{i}^{'}) \cap ({\overline{Y}} - \overline{Y_0})\), where \(x_i \in Y_0\) and \(x_i^{'} \in \overline{Y_0}\). Combining with the above claim of n, we have
Without loss of generality, we assume that \(D_{{\overline{Y}}} \le D_{Y}\). Thus, we have:
Since each edge of S is incident with at most \((r - 1)\) vertices of \(Y_0\), we have \(|Y_0| \le (r - 1)\lambda\). And it is easy to see that \(|Y_0| + |\overline{Y_0}| \le \lambda r\), \(|X_i| \le (d(x_i) - 1)(r - 1) \le (\Delta - 1)(r - 1)\) and \(|X_i^{'}| \le (\Delta - 1)(r - 1)\). It follows that
Let \(a = (\Delta - 1)(r - 1)\), one has
Using the fact that \(D_{Y} \ge 1\), \(D_{{\overline{Y}}} \ge 1\) and \(D_{Y} + D_{{\overline{Y}}} + 1 \le D\), one can show that
We remind that the above relation has been computed with the assumption that \(\lambda < \delta\). Thus, we have
This completes the proof. \(\square\)
See Fig. 3, we give an r-uniform linear hypergraph \(H_3\) which is not maximally edge-connected and reaches the upper bound presented in Theorem 4.2. \(H_3\) is constructed by r copies of \(H_0\) and adding a new edge consisting of all the vertices of degree r, where \(H_0\) is also an r-uniform linear hypergraph. Theorem 4.2 yields the following result whose special case \(r = 2\) is Theorem 4.1.
Theorem 4.3
Let H be an r-uniform linear hypergraph with maximum degree \(\Delta \ge 3\), minimum degree \(\delta\) and diameter D. Then \(\lambda (H) = \delta (H)\) when
5 A sufficient condition about size
In this section, we will work towards a sufficient condition for maximally edge-connected and super-\(\lambda\) r-uniform hypergraphs. And, we need the following definition. For two integers n and k, we define \(\left( {\begin{array}{c}n\\ k\end{array}}\right) = \frac{n!}{k!(n-k)!}\) when \(k \le n\) and \(\left( {\begin{array}{c}n\\ k\end{array}}\right) = 0\) when \(k > n\).
Definition 5.1
For two integers \(\delta\) and r with \(r \ge 2\), define \(t = t(\delta , r)\) to be the largest integer such that \(\left( {\begin{array}{c}t-1\\ r-1\end{array}}\right) \le \delta\). That is, t is the integer satisfying \(\left( {\begin{array}{c}t-1\\ r-1\end{array}}\right) \le \delta < \left( {\begin{array}{c}t\\ r-1\end{array}}\right)\).
Lemma 5.2
Let H be a connected r-uniform hypergraph of order n, size m, minimum degree \(\delta\) and edge-connectivity \(\lambda\). If \(\lambda < \delta\), then
where \(t = t(\delta , r)\).
Proof
Let S be an arbitrary minimum edge-cut and let X denote the vertex set of the component of \(H - S\) with minimum number of vertices, and \(Y = V(H) - X\). We first show that \(|Y| \ge |X| \ge t\). Suppose \(|X| \le t - 1\). Then we obtain
and thus,
If \(|X| = 1\), then \(\lambda = \delta\), contradicting \(\lambda < \delta\). So, \(|X| \ge r\), by the fact that H[X] is connected, and the inequality (2) is impossible. Therefore, we have \(t \le |X| \le |Y| \le n - t\), and
This bound leads to
Since \(f(x) = \left( {\begin{array}{c}x\\ r\end{array}}\right) + \left( {\begin{array}{c}n - x\\ r\end{array}}\right)\) is a decreasing function when \(1 \le x \le \frac{n}{2}\) and a increasing function when \(\frac{n}{2} \le x \le n\), we obtain
\(\square\)
Theorem 5.3
Let H be a connected r-uniform hypergraph of order n, size m, minimum degree \(\delta\) and edge-connectivity \(\lambda\). If
then \(\lambda = \delta\), unless that H is a hypergraph obtained from \(K_t^{r} \cup K_{n-t}^{r}\) by adding \(\delta - 1\) edges, where \(t = t(\delta , r)\).
Proof
If \(m > \left( {\begin{array}{c}n-t\\ r\end{array}}\right) + \left( {\begin{array}{c}t\\ r\end{array}}\right) + \delta - 1\), then by Lemma 5.2, we have \(\lambda = \delta\). If \(m = \left( {\begin{array}{c}n-t\\ r\end{array}}\right) + \left( {\begin{array}{c}t\\ r\end{array}}\right) + \delta - 1\), then by the proof of Lemma 5.2, we have that the inequalities in the proof of Lemma 5.2 must by equalities, which implies that \(\lambda = \delta - 1\), \(|X| = t\), \(|Y| = n - t\), \(H[X] \cong K_t^{r}\) and \(H[Y] \cong K_{n-t}^{r}\). This completes the proof. \(\square\)
Corollary 5.4
([17]). Let G be a connected graph of order n, size m, minimum degree \(\delta\) and edge-connectivity \(\lambda\). If
then \(\lambda = \delta\), unless that G is a graph obtained from \(K_{\delta +1} \cup K_{n-\delta -1}\) by adding \(\delta - 1\) edges.
Proof
When \(r = 2\), then \(t = \delta + 1\) by the Definition 5.1. Thus, the result follows from Theorem 5.3. \(\square\)
Lemma 5.5
Let H be a connected r-uniform hypergraph of order n, size m, minimum degree \(\delta\) and edge-connectivity \(\lambda\). If H is not super-\(\lambda\), then
where \(t = t(\delta , r)\).
Proof
Let S be an arbitrary minimum edge-cut such that every component of \(H - S\) has at least two vertices. Let X denote the vertex set of the component of \(H - S\) with minimum number of vertices, and \(Y = V(H) - X\). Clearly, \(|Y| \ge |X| \ge 2\). We first show that \(|Y| \ge |X| \ge t - 1\). Suppose \(|X| \le t - 2\). Then we obtain
and thus,
a contradiction. Therefore, we have \(t - 1 \le |X| \le |Y| \le n - t + 1\), and
and so
\(\square\)
By the same argument as that of Theorem 5.3 and Corollary 5.4, the following results follows.
Theorem 5.6
Let H be a connected r-uniform hypergraph of order n, size m, minimum degree \(\delta\) and edge-connectivity \(\lambda\). If
then H is super-\(\lambda\), unless \(t \ge 3\) and H is a hypergraph obtained from \(K_{t-1}^{r} \cup K_{n-t+1}^{r}\) by adding \(\delta\) edges between \(K_{t-1}^{r}\) and \(K_{n-t+1}^{r}\) such that \(\delta (H) = \delta\), where \(t = t(\delta , r)\).
Corollary 5.7
([17]). Let G be a connected graph of order n, size m, minimum degree \(\delta\) and edge-connectivity \(\lambda\). If
then G is super-\(\lambda\), unless \(\delta \ge 2\) and G is a graph obtained from \(K_{\delta } \cup K_{n-\delta }\) by adding \(\delta\) edges between \(K_{\delta }\) and \(K_{n-\delta }\) such that \(\delta (G) = \delta\).
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Communicated by Sharad S Sane.
The research is supported by NSFC (No. 11531011), XJTCDP (NO. 04231200746) and XJUDP (NO. 62031224601).
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Zhao, S., Li, D. & Meng, J. Edge-connectivity in hypergraphs. Indian J Pure Appl Math 52, 837–846 (2021). https://doi.org/10.1007/s13226-021-00052-5
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DOI: https://doi.org/10.1007/s13226-021-00052-5