1 Introduction

For graphs \(G_1,\dots ,G_k\), the Ramsey number \(r_k(G_1,\dots ,G_k)\) is defined as the minimum N such that if edges of \(K_N\) are colored by k colors, then there is a monochromatic \(G_i\) in a color i with \(1\le i\le k\). We shall write \(r_{k+1}(G,\dots ,G,G_{k+1})\) as \(r_{k+1}(G;G_{k+1})\) in short, and write two color Ramsey number \(r_2(G_1,G_2)\) as \(r(G_1,G_2)\), and r(GG) as r(G).

Call graph \(B^{(m)}_n\) a book that consists of n copies of \(K_{m+1}\) that share a common \(K_m\). As usual, we write \(B^{(2)}_n\) as \(B_n\). Book graph plays an important role in graph Ramsey theory. It was shown by Rousseau and Sheehan [10] that \(r(B_n)=4n+2\) for infinitely many n, and \(r(B_m,K_n)\) was bounded from above by Li and Rousseau [6]. Moreover, Conlon [3] obtained \(r(B^{(m)}_n)\sim 2^m n\) as \(n\rightarrow \infty \).

For large n, complete bipartite graph \(K_{m,n}\) and book \(B_n^{(m)}\) seem to look like each other, and the Ramsey numbers involving them are known to be close in some cases. Chung and Graham [2] established

$$\begin{aligned} r_k(K_{m,n})\le (n-1)(k+k^{1/m})^m \end{aligned}$$

for \(k\ge 2, n\ge m\ge 2\), and

$$\begin{aligned} r_k(K_{2,n})\le (n-1)k^2+k+2. \end{aligned}$$

Recently, Wang et al. obtained the following result. For positive functions f(n) and g(n), we write \(f(n)=o(g(n))\) if \(f(n)/g(n)\rightarrow 0\) as \(n\rightarrow \infty \).

Lemma 1

[11] Let integers \(k\ge 1\) and \(s\ge t\ge m\ge 1\). Then

$$\begin{aligned} r_{k+1}(K_{t,s}; K_{m,n})\le n + (1+o(1))(s-t+1)^{1/t} k m n^{1-1/t} \end{aligned}$$
(1)

as \(n\rightarrow \infty \). There are infinitely many n such that (1) becomes an equality for \(r_{k+1}(K_{2,s}; K_{1,n})\), \(r_{k+1}(K_{3,3}; K_{1,n})\), \(r(K_{2,s}, K_{2,n})\) and \(r(K_{3,3}, K_{m,n})\) for \(m \le 3\).

Since \(r_{k+1}(G;K_{m,n})\le r_{k+1}(G;B^{(m)}_n)\), we shall generalize Lemma 1 by replacing \(K_{m,n}\) with \(B^{(m)}_n\).

Theorem 1

Let \(s\ge t\ge 2\) and \(k,m\ge 1\) be fixed integers. If n is large, then

$$\begin{aligned} r_{k+1}(K_{t,s};B_n^{(m)})\le n+ (1+o(1)) (s-t+1)^{1/t} k m n^{1-1/t}. \end{aligned}$$
(2)

Corollary 1

Let \(s\ge 2\) and \(m\ge 1\) be fixed integers. Then, there are infinitely many n such that

$$\begin{aligned} r(K_{2,s}, B_n^{(m)})= n + (1+o(1)) m \sqrt{(s-1) n}, \end{aligned}$$

and \(r(K_{2,s}, K_{m,n})= n + (1+o(1)) m \sqrt{(s-1) n}\) as such \(n\rightarrow \infty \).

Corollary 2

Let \(m\ge 1\) be an integer. Then, there are infinitely many n such that

$$\begin{aligned} r(K_{3,3}, B_n^{(m)})= n + (1+o(1)) m n^{2/3}, \end{aligned}$$

and \(r(K_{3,3}, K_{m,n})= n + (1+o(1)) m n^{2/3}\) as such \(n\rightarrow \infty \).

Ramsey numbers involving cycles and large stars have attracted much attention. Parsons [9] obtained

$$\begin{aligned} r(C_4,K_{1,n})\le n+\lceil \sqrt{n}\,\rceil +1 \end{aligned}$$

for any \(n\ge 2\), and the equality holds for infinitely many n, and if q is a prime power, then \(r(C_4,K_{1,q^2})=q^2+q+1\) and \(r(C_4,K_{1,q^2+1})=q^2+q+2\).

Zhang, Chen and Cheng [13] showed that

$$\begin{aligned} r_{k+1}(C_4; K_{1,n}) \le n+ \lceil k\sqrt{n +(k^2+2k-3)/4}\rceil +\frac{k(k+1)}{2}, \end{aligned}$$

and \(r_3(C_4;K_{1,n})=n+\sqrt{4n+1}+3\) for infinitely many n.

Liu and Li [8] determined \(r(C_{2t+1}, B^{(m)}_{n})=2(m+n-1)+1\) for \(t,m\ge 1\), and Lin and Peng [7] obtained \(r(C_n,B^{(m)}_n)=(m+o(1))n\) as \(m\ge 3\) and \(n\rightarrow \infty \).

We shall investigate the behavior of \(r_{k+1}(C_{2t};B^{(m)}_{n})\) for large n as follows.

Theorem 2

Let kt and m be positive integers. If n is large, then

$$\begin{aligned} r_{k+1}(C_{2t};B^{(m)}_{n})\le n+ (1+o(1))c_t k m n^{1/t}, \end{aligned}$$

where \(c_t>0\) is a constant depends on t only. Furthermore, for each \(t\in \{2,3,5\}\), there are infinitely many n such that

$$\begin{aligned} r_{k+1}(C_{2t};B^{(m)}_{n})) \ge n+ (1-o(1))c k n^{1/t} \end{aligned}$$

for such n if n is large, where \(c=c(t)>0\) is a constant.

2 Proofs of Main Results

For a graph G, denote by v(G) and e(G) the numbers of vertices and edges of G, respectively. A graph G is said to be H-free if G contains no H as a subgraph. The Turán number ex(nH) of H is defined as the maximum e(G) of an H-free graph G of order n.

A well known result of Kövari, Sós and Turán [5] tells us

$$\begin{aligned} ex(N,K_{t,s})\le \frac{1}{2} \big [(s-1)^{1/t}N^{2-1/t}+(t-1)N\big ]\;\; (s\ge t\ge 1). \end{aligned}$$

Füredi [4] showed

$$\begin{aligned} ex(N,K_{t,s})\le \frac{1}{2}\big [(s-t+1)^{1/t} N^{2-1/t}+tN+tN^{2-2/t}\big ] \end{aligned}$$

for \(s\ge t\ge 1\). Thus we know that if \(s\ge t\ge 2\), then

$$\begin{aligned} ex(N,K_{t,s})\le (1+o(1))\frac{1}{2}(s-t+1)^{1/t} N^{2-1/t} \end{aligned}$$
(3)

as \(N\rightarrow \infty \). For even cycles \(C_{2t}\), Bondy and Simonovits [1] proved for any \(t\ge 2\),

$$\begin{aligned} ex(N,C_{2t})\le c_t N^{1+1/t} \end{aligned}$$
(4)

for large N, where \(c_t>0\).

We also need the following result from [11], for which we can replace the condition \(ex(N,H)\sim cN^{2-\eta }\) with \(ex(N,H)\ge cN^{2-\eta }\) from the proof as we need a lower bound for \(r_{k+1}(H;K_{1,n})\) only. Let \(\delta (G)\) and \(\varDelta (G)\) be the minimum and maximum degree of graph G, respectively.

Lemma 2

[11] Let H be a bipartite graph with \(ex(N,H)\ge cN^{2-\eta }\) as \(N\rightarrow \infty \), where c and \(\eta \) are positive constants. If there are extremal graphs \(G_N\) of order N for ex(NH) such that \(\delta (G_N)\sim \varDelta (G_N)\) as \(N\rightarrow \infty \), then

$$\begin{aligned} r_{k+1}(H; K_{1,n})\ge n + (1-\epsilon )2kc n^{1-\eta } \end{aligned}$$

for large n, where \(\epsilon >0\).

In following proofs, when we color the edges of \(K_N\) by \(k+1\) colors, we shall write the monochromatic graph induced by edges in color i as \(G_i\) for \(1\le i\le k+1\). For a vertex v, we denote by \(d_i(v)\) as the degree of v in the graph \(G_i\), and thus \(\sum _{i=1}^{k+1}d_i(v)=N-1\) for any v.

We shall not distinguish \(\lceil x\rceil \) and \(\lfloor x\rfloor \) from x for large x as the differences are negligible for asymptotic computation.

Proof of Theorem 1

For any \(\epsilon >0\), let

$$\begin{aligned} \ell _m= (1+\epsilon ) k m (s-t+1)^{1/t}n^{1-1/t} \end{aligned}$$

and \(N_m=n+\ell _m\). We shall show

$$\begin{aligned} r_{k+1}(K_{t,s};B_n^{(m)})\le N_m = n+ \ell _m \end{aligned}$$
(5)

for all large n by induction on m.

To simplify the proof, we shall start at \(m=0\) instead of \(m=1\), in which \(K_{0,n}\) is admitted as \({\overline{K}}_n\) that consists of n vertices without any edge.

For the case \(m=0\), the claimed upper bound follows as any graph of order \(N_0=n\) contains \({\overline{K}}_n\) as a subgraph.

Next, we assume that (5) holds for any \(m\ge 0\), and we shall show that it holds for \(m+1\).

Consider an edge coloring of \(K_{N_{m+1}}\) by \(k+1\) colors. We shall show that there is a \(B_n^{(m+1)}\) in \(G_{k+1}\) or a \(K_{t,s}\) in some \(G_i\) for \(1\le i\le k\).

If there is a vertex v such that \(d_{k+1}(v)\ge r_{k+1}(K_{t,s};B_n^{(m)})\), then the neighborhood of v in \(G_{k+1}\), whose edges are colored by \(k+1\) colors, contains a subgraph \(B_n^{(m)}\) in color \(k+1\), hence that and v form a subgraph \(B_n^{(m+1)}\) of \(G_{k+1}\), and thus we are done. So we may assume that for each vertex v,

$$\begin{aligned} d_{k+1}(v)\le r_{k+1}(K_{t,s};B_n^{(m)})-1 \le n+\ell _m -1, \end{aligned}$$

in which the second inequality comes from induction hypothesis. So we have

$$\begin{aligned} e(G_{k+1}) =\frac{1}{2} \sum _{v} d_{k+1}(v) \le \frac{1}{2}N_{m+1} (n+\ell _m -1). \end{aligned}$$

Hence

$$\begin{aligned} \sum _{i=1}^k e(G_i)= & {} \left( {\begin{array}{c}N_{m+1}\\ 2\end{array}}\right) -e(G_{k+1}) \ge \frac{N_{m+1}}{2} (N_{m+1}-n-\ell _m) \\= & {} \frac{N_{m+1}}{2}(\ell _{m+1}-\ell _m), \end{aligned}$$

where

$$\begin{aligned} \ell _{m+1}-\ell _m= & {} \Big [(1+\epsilon )(m+1) -(1+\epsilon )m \Big ]k(s-t+1)^{1/t}n^{1-1/t} \\= & {} (1+\epsilon ) k (s-t+1)^{1/t} n^{1-1/t} \\\ge & {} \big (1+\frac{\epsilon }{2}\big )k(s-t+1)^{1/t} N_{m+1}^{1-1/t} \end{aligned}$$

as \(n\sim N_{m+1}\) for large n. Therefore, there is a \(G_j\) with \(1\le j\le k\) such that

$$\begin{aligned} e(G_j)\ge \frac{1}{k} \sum _{i=1}^k e(G_i)\ge \frac{1}{2} \big (1+\frac{\epsilon }{2}\big )(s-t+1)^{1/t} N_{m+1}^{2-1/t}>ex(N_{m+1},K_{t,s}), \end{aligned}$$

where the last inequality comes from (3). Thus \(G_j\) contains a \(K_{t,s}\), and then we get the desired upper bound. \(\square \)

Proof of Corollary 1

Lemma 7 in [11] says that

$$\begin{aligned} r(K_{2,s},K_{m,n})\ge n+(1+o(1))m\sqrt{(s-1)n} \end{aligned}$$

for any \(s\ge 2\), \(m\ge 1\), and infinitely many n, which and Theorem 1 for \(k=1\) and \(t=2\) imply the desired statements since \(r(K_{2,s};B_n^{(m)})\ge r(K_{2,s};K_{m,n})\). \(\square \)

Proof of Corollary 2

Lemma 9 in [11] says that

$$\begin{aligned} r(K_{3,3},K_{m,n})\ge n+(1+o(1))mn^{2/3} \end{aligned}$$

for any \(m\ge 1\) and infinitely many n, which and Theorem 1 for \(k=1\) imply the desired statements since \(r(K_{3,3};B_n^{(m)})\ge r(K_{3,3};K_{m,n})\). \(\square \)

Proof of Theorem 2

For any \(\epsilon >0\), let

$$\begin{aligned} \ell _m = (1+\epsilon )c_tkm n^{1/t} \end{aligned}$$

and \(N_m=n+\ell _m\), where \(c_t>0\) is the constant in (4). We shall show

$$\begin{aligned} r_{k+1}(C_{2t};B_n^{(m)}) \le N_m =n+\ell _m \end{aligned}$$
(6)

for all large n. The proof is similar to that for Theorem 1 by induction on \(m\ge 0\), and we go to the inductive step directly to show (6) for case \(m+1\) by considering an edge coloring of \(K_{N_{m+1}}\) with \(k+1\) colors, in which \(G_{k+1}\) contains no \(B_n^{(m)}\).

The similar analysis and induction hypothesis imply

$$\begin{aligned} \sum _{i=1}^k e(G_i) \ge \left( {\begin{array}{c}N_{m+1}\\ 2\end{array}}\right) -e(G_{k+1}) \ge \frac{N_{m+1}}{2}(\ell _{m+1}-\ell _m), \end{aligned}$$

where

$$\begin{aligned} \ell _{m+1}-\ell _m \ge \big (1+\frac{\epsilon }{2}\big ) c_t k N_{m+1}^{1/t}. \end{aligned}$$

So some \(G_j\) with \(1\le j\le k\) has \(e(G_j)> ex(N_{m+1},C_{2t})\) and \(G_j\) contains \(C_{2t}\).

Next, for \(t\in \{2,3,5\}\), we shall show that there are infinitely many n such that

$$\begin{aligned} r_{k+1}(C_{2t};B^{(m)}_{n}) \ge n+ (1-\epsilon )c k n^{1/t} \end{aligned}$$

for these n. To this end, the starting point is the result of Wenger [12] as

$$\begin{aligned} ex(n,C_{2t}) \ge c n^{1+1/t} =c n^{2-(t-1)/t}, \end{aligned}$$

where \(c=c(t)>0\) is a constant. Thus Lemma 2 implies

$$\begin{aligned} r_{k+1}(C_{2t};K_{1,n})\ge n+ (1-o(1))2ck n^{1-(t-1)/t} = n+ (1-o(1))2ck n^{1/t}, \end{aligned}$$

and it follows by \(r_{k+1}(C_{2t};B_n^{(m)})\ge r_{k+1}(C_{2t};K_{1,n})\) as required. \(\square \)