Keywords

10.1 Introduction

Let S be a finite domain in \(\mathbb{R}^{2}\), bounded by a simple, closed, C 2 curve \(\partial S\). We denote by x and y generic points in \(S \cup \partial S\) and by | xy | the distance between x and y in the Cartesian metric. Also, let C 0, α(∂ S) and C 1, α(∂ S), α ∈ (0, 1), be, respectively, the spaces of Hölder continuous and Hölder continuously differentiable functions on \(\partial S\). In what follows, Greek and Latin indices take the values 1, 2 and 1, 2, 3, respectively, and a superscript T denotes matrix transposition.

For any function f continuous on \(\partial S\), we define the ‘calibration’ functional p by

$$\displaystyle{ pf =\int \limits _{\partial S}f\,ds. }$$

Using the fundamental solution for the two-dimensional Laplacian

$$\displaystyle{ g(x,y) = -\frac{1} {2\pi }\,\ln \vert x - y\vert, }$$

we define the single-layer harmonic potential of density φ by

$$\displaystyle{ (V \varphi )(x) =\int \limits _{\partial S}g(x,y)\varphi (y)\,ds(y). }$$

The proof of the following assertion can be found, for example, in [Co94] or [Co00].

Theorem 1.

For any α ∈ (0,1), there are a unique nonzero function Φ ∈ C 0,α (∂S) and a unique number ω such that

$$\displaystyle{ V \varPhi =\omega \quad \mbox{ on $\partial S$},\quad p\varPhi = 1. }$$

It is easy to see that Φ and ω depend on g and ∂ S.

The numbers 2π ω and e −2π ω are called Robin’s constant and the logarithmic capacity of ∂ S.

For a circle with the center at the origin and radius R, both Φ and ω can be determined explicitly:

$$\displaystyle{ \varPhi = \frac{1} {2\pi R},\quad \omega = -\frac{1} {2\pi }\,\ln R. }$$

For other boundary curves, Φ and ω are practically impossible to determine analytically and must be computed by numerical methods.

If the solution of the Dirichlet problem in S with data function f on ∂ S is sought as u = V φ, then φ is a solution of the (weakly singular) first-kind boundary integral equation

$$\displaystyle{ V \varphi = f\quad \mbox{ on $\partial S$}. }$$

This is a well-posed problem if and only if ω ≠ 0. If ω = 0, the above equation has infinitely many solutions, which are expressed in terms of Φ.

10.2 Plane Elastic Strain

Consider a plate made of a homogeneous and isotropic material with Lamé constants λ and μ, which undergoes deformations in the (x 1, x 2)-plane. If the body forces are negligible, then its (static) displacement vector u = (u 1, u 2)T satisfies the equilibrium system of equations [Co00]

$$\displaystyle{ Au = 0\quad \mbox{ in $S$}, }$$

where

$$\displaystyle{ A(\partial _{1},\partial _{2}) = \left (\begin{array}{*{10}c} \mu \varDelta +(\lambda +\mu )\partial _{1}^{2} & (\lambda +\mu )\partial _{1}\partial _{2} \\ (\lambda +\mu )\partial _{1}\partial _{2} & \mu \varDelta +(\lambda +\mu )\partial _{2}^{2} \end{array} \right ). }$$

It is not difficult to show [Co00] that the columns F (i) of the matrix

$$\displaystyle{ F = \left (\begin{array}{rrr} 1&0& x_{2} \\ 0&1& - x_{1} \end{array} \right ) }$$

form a basis for the space of rigid displacements.

The ‘calibrating’ vector-valued functional p is defined for continuous 2 × 1 vector functions f by

$$\displaystyle{ pf =\int \limits _{\partial S}F^{\mathrm{T}}f\,ds. }$$

A matrix of fundamental solutions for A is [Co00]

$$\displaystyle\begin{array}{rcl} & & D(x,y) = - \frac{1} {4\pi \mu (\gamma +1)} {}\\ & & \quad \times \left (\begin{array}{*{10}c} 2\gamma \ln \vert x - y\vert + 2\gamma + 1 -\dfrac{2(x_{1} - y_{1})^{2}} {\vert x - y\vert ^{2}} & -\dfrac{2(x_{1} - y_{1})(x_{2} - y_{2})} {\vert x - y\vert ^{2}} \\ -\dfrac{2(x_{1} - y_{1})(x_{2} - y_{2})} {\vert x - y\vert ^{2}} & 2\gamma \ln \vert x - y\vert + 2\gamma + 1 -\dfrac{2(x_{2} - y_{2})^{2}} {\vert x - y\vert ^{2}} \end{array} \right ), {}\\ & & \qquad \qquad \qquad \qquad \qquad \quad \qquad \qquad \gamma = \frac{\lambda +3\mu } {\lambda +\mu }. {}\\ \end{array}$$

The single-layer potential of density φ is defined by

$$\displaystyle{ (V \varphi )(x) =\int \limits _{\partial S}D(x,y)\varphi (y)\,ds(y). }$$

The proof of the following assertion can be found in [Co00].

Theorem 2.

There is a unique 2 × 3 matrix function Φ ∈ C 0,α (∂S) and a unique 3 × 3 constant symmetric matrix \(\mathcal{C}\) such that the columns Φ (i) of Φ are linearly independent and

$$\displaystyle{ V \varPhi = F\mathcal{C}\quad \mbox{ on $\partial S$},\quad p\varPhi = I, }$$

where I is the identity matrix.

Clearly, Φ and \(\mathcal{C}\) depend on A, D, and ∂ S.

In the so-called alternative indirect method [Co00], the solution of the Dirichlet problem in S with data function f on ∂ S is sought in the form

$$\displaystyle{ u = V \varphi. }$$
(10.1)

Then the problem reduces to the (weakly singular) boundary integral equation

$$\displaystyle{ V \varphi = f\quad \mbox{ on $\partial S$}. }$$
(10.2)

Theorem 3.

Equation (10.2) has a unique solution φ ∈ C 0,α (∂S), α ∈ (0,1), for any f ∈ C 1,α (∂S) if and only if \(\det \mathcal{C}\not =0\) . In this case, (10.1) is the unique solution of the Dirichlet problem.

If \(\det \mathcal{C} = 0\), then the unique solution of the Dirichlet problem is obtained by solving an ill-posed modified boundary integral equation whose infinitely many solutions are constructed with Φ and \(\mathcal{C}\).

In the so-called refined indirect method [Co00], the solution of the Dirichlet problem is sought as a pair {φ, c} such that

$$\displaystyle{ u = V \varphi - Fc\quad \mbox{ in $S$},\quad p\varphi = s, }$$

where s a constant 3 × 1 vector chosen (arbitrarily) a priori and c is a constant 3 × 1 vector. This leads to the system of boundary integral equations

$$\displaystyle{ V \varphi - Fc = f\quad \mbox{ on $\partial S$},\quad p\varphi = s. }$$
(10.3)

Theorem 4.

System (10.3) has a unique solution {φ, c} with φ ∈ C 0,α (∂S) for any f ∈ C 1,α (∂S), α ∈ (0,1), and any s.

It is important to evaluate the arbitrariness in the representation of the solution with respect to the prescribed ‘calibration’ s.

Theorem 5.

If {φ (1) , c (1) }, {φ (2) , c (2) } are two solutions of (10.3) constructed with s (1) and s (2) , respectively, then

$$\displaystyle\begin{array}{rcl} & & \varphi ^{(2)} =\varphi ^{(1)} +\varPhi (s^{(2)} - s^{(1)}), {}\\ & & c^{(2)} = c^{(1)} + \mathcal{C}(s^{(2)} - s^{(1)}). {}\\ \end{array}$$

It is not easy to compute Φ and \(\mathcal{C}\) analytically, or even numerically, in arbitrary domains S, but this can be accomplished if S is a circular disk. Let ∂ S be the circle with center at the origin and radius R. In this case, Φ and \(\mathcal{C}\) can be determined analytically as

$$\displaystyle{ \varPhi = \frac{1} {2\pi R}\,\left (\begin{array}{ccr} 1&0& R^{-2}x_{ 2} \\ 0&1& - R^{-2}x_{1} \end{array} \right ), }$$
$$\displaystyle\begin{array}{rcl} & & \mathcal{C} = - \frac{1} {4\pi \mu (\lambda +2\mu )R^{2}} {}\\ & & \qquad \qquad \times \left (\begin{array}{*{10}c} (\lambda +3\mu )R^{2}(\ln R + 1)& 0 & 0 \\ 0 &(\lambda +3\mu )R^{2}(\ln R + 1)& 0 \\ 0 & 0 &-(\lambda +\mu ) \end{array} \right ).\quad {}\\ \end{array}$$

Clearly, \(\det \mathcal{C} = 0\) if and only if \(R = e^{-1}\).

Analytic computation of Φ and \(\mathcal{C}\) is practically impossible for non-circular domains, and must be performed numerically.

We choose four 3 × 1 constant vectors s (0), s (i) such that the set {s (i)s (0)} is linearly independent, and form the 3 × 3 matrix \(\varSigma\) with columns s (i)s (0). Also, we choose an arbitrary function f. Next, we compute the solutions {φ (0), c (0)}, {φ (i), c (i)} of (10.3) corresponding to s (0), s (i), respectively, and f, by the refined indirect method, then form the 2 × 3 matrix function Ψ with columns φ (i)φ (0) and the constant 3 × 3 matrix Γ with columns c (i)c (0).

From Theorem 4 it follows that

$$\displaystyle\begin{array}{rcl} \varphi ^{(i)} -\varphi ^{(0)}& =& \varPhi (s^{(i)} - s^{(0)}), {}\\ c^{(i)} - c^{(0)}& =& \mathcal{C}(s^{(i)} - s^{(0)}), {}\\ \end{array}$$

or, what is the same,

$$\displaystyle{ \varPhi \varSigma =\varPsi,\quad \mathcal{C}\varSigma =\varGamma; }$$

hence,

$$\displaystyle{ \varPhi =\varPsi \varSigma ^{-1},\quad \mathcal{C} =\varGamma \varSigma ^{-1}. }$$

A similar analysis can be performed for other two-dimensional linear elliptic systems with constant coefficients—for example, the system modeling bending of elastic plates with transverse shear deformation [Co00]. No apparent connection exists between the matrix \(\mathcal{C}\) and the characteristic constant ω of ∂ S.

10.3 Numerical Examples

Consider a steel plate with scaled Lamé coefficients

$$\displaystyle{ \lambda = 11.5,\quad \mu = 7.69, }$$

and let ∂ S (see Figure 10.1) be the curve of parametric equations

$$\displaystyle\begin{array}{rcl} x_{1}(t)& =& 2\cos (\pi t) -\tfrac{4} {3}\,\cos (2\pi t) + \tfrac{10} {3}, {}\\ x_{2}(t)& =& 2\sin (\pi t) + 2,\quad 0 \leq t \leq 2. {}\\ \end{array}$$
Fig. 10.1
figure 1

The boundary curve ∂ S.

We choose the vectors

$$\displaystyle\begin{array}{rcl} & s^{(0)} = \left (\begin{array}{*{10}c} 1\\ 1 \\ 1 \end{array} \right ),\quad s^{(1)} = \left (\begin{array}{*{10}c} 1\\ 0 \\ 0 \end{array} \right ),\quad s^{(2)} = \left (\begin{array}{*{10}c} 0\\ 1 \\ 0 \end{array} \right ),\quad s^{(3)} = \left (\begin{array}{*{10}c} 0\\ 0 \\ 1 \end{array} \right ),& {}\\ & f(x) = \left (\begin{array}{*{10}c} 1\\ 0 \end{array} \right ). & {}\\ \end{array}$$

The approximating functions for computing φ (0)(t) and φ (i)(t) are piecewise cubic Hermite splines on 12 knots; that is, the interval 0 ≤ t ≤ 2 is divided into 12 equal subintervals. Then the characteristic matrix (with entries rounded off to 5 decimal places) is

$$\displaystyle{ \mathcal{C} = \left (\begin{array}{rrr} - 0.01627& - 0.01083& - 0.00370\\ - 0.01083 & - 0.00892 & 0.00542 \\ - 0.00370& 0.00542& 0.00185 \end{array} \right ). }$$

Here,

$$\displaystyle{ \det \mathcal{C} = 1.08273 \times 10^{-6}. }$$

The graphs of the components Φ α i of Φ are shown in Figure 10.2.

Fig. 10.2
figure 2

Graphs of the Φ α i .

As a second example, consider the ‘expanding’ ellipse ∂ S of parametric equations

$$\displaystyle\begin{array}{rcl} x_{1}(t)& =& 2k\cos (\pi t), {}\\ x_{2}(t)& =& k\sin (\pi t),\quad 0 \leq t \leq 2. {}\\ \end{array}$$

The graph of \(\det \mathcal{C}\) as a function of k is shown in Figure 10.3.

Fig. 10.3
figure 3

Graph of \(\det \mathcal{C}\).

Here, \(\det \mathcal{C} = 0\) for k = 0. 22546 and k = 0. 26934.