1 Introduction

There exists tomographic probability representations of quantum states [1, 2]. Among these representations the optical tomography scheme based on relations of the optical tomogram with the Wigner function [3] is discussed in [4, 5] as well as the symplectic tomography scheme introduced in [2, 6]. The spin tomography was constructed in [7,8,9]. The center-of-mass tomography was introduced in [10] and developed in [11]. The properties of the center-of-mass tomogram are investigated in the context of the central limit theorem in [12, 13]. The review of tomographic picture of quantum mechanics is presented in [1, 14]. All the tomographic schemes provide description of quantum states in terms of fair probability distributions. The tomograms of the states are connected by integral transforms with quasiprobability distributions like the Wigner function, Husimi Q-function [15] and Glauber-Sudarshan P-function [16, 17]. The aim of our work is to study in details the center-of-mass tomographic probability representations of multimode electromagnetic field states. The tomographic approach can be presented in terms of the quantizer-dequantizer formalism [18]. In the work we use this formalism to find the relation of the Wigner function, Weyl symbols of observables and integral kernels determining the star-product of the observable symbols e.g. Grönewold kernel [19] with the corresponding center-of-mass tomograms in the case of multimode electromagnetic field states. The paper is organized as follows. In Section 2 we review the quantizer-dequantizer formalism (star-product formalism). In Section 3 we present the contribution to the center-of-mass tomography. The dual center-of-mass tomography is considered and explicit form of the star-product integral kernel of two-mode center-of-mass tomographic symbols is obtained. Connection between the Weyl map and the center-of-mass map is given in Section 4. Some other modifications of the center-of-mass tomography are developed in Section 5. An ambiguity in the center-of-mass tomographic description of quantum states is discussed in Section 6. Example of superpositions of two-mode coherent states is gived in Section 7. Prospectives and conclusions are formulated in Section 8.

2 The Star-Product Scheme

In this section we review the star-product formalism following [18]. In quantum mechanics, physical observables are represented by operators acting in a given Hilbert space \(\mathcal {H}\). According to the star-product formalism one can construct an invertible map of operators onto functions. Thus one can use functions instead of operators. The invertible map can be constructed with the aid of two operators the quantizer \(\hat {D}(\mathbf {x})\) and the dequantizer \(\hat {U}(\mathbf {x})\) labeled by a vector with \(n\) components \(\mathbf {x}=(x_{1},x_{2},\ldots ,x_{n})\). Given an operator \(\hat {A}\) acting in \(\mathcal {H}\) the corresponding function (we call it the symbol of the operator \(\hat {A}\)) is defined by

$$ w_A(\mathbf{x})=\text{Tr}[\hat{A}\,\hat{U}(\mathbf{x})]. $$
(1)

The formula

$$ \hat{A}=\int w_A(\mathbf{x})\hat{D}(\mathbf{x})d\mathbf{x} $$
(2)

allows to reconstruct the operator from its simbol. In the latter formula an integration over continuous and a sum over discreate components of the vector \(\mathbf {x}\) are assumed. Let us notice that formulae (1) and (2) are compatible if for the symbol \(w_{A}(\mathbf {x})\) of any operator \(\hat {A}\) the following identity holds true

$$ w_A(\mathbf{x})=\int w_A(\mathbf{x^{\prime}})\text{Tr}[\hat{D}(\mathbf{x^{\prime}})\hat{U}(\mathbf{x})]d\mathbf{x^{\prime}}. $$
(3)

Deriving the above formula, we assumed that one can exchange the trace with the integral. Let \(w_{A}(\mathbf {x})\) and \(w_{B}(\mathbf {x})\) be the symbols of two operators \(\hat {A}\) and \(\hat {B}\), then the symbol corresponding to the operator \(\hat {A}\hat {B}\) is

$$ w_{AB}(\mathbf{x})=\text{Tr}[\hat{A}\,\hat{B}\,\hat{U}(\mathbf{x})]=\int w_A(\mathbf{x}_2)w_B(\mathbf{x}_1)\text{Tr}[\hat{D}(\mathbf{x}_2)\hat{D}(\mathbf{x}_1)\hat{U}(\mathbf{x})]d\mathbf{x}_1 d\mathbf{x}_2. $$
(4)

The symbol \(w_{AB}(\mathbf {x})\) is called the star-product of symbols \(w_{A}(\mathbf {x})\) and \(w_{B}(\mathbf {x})\) and denoted by \((w_{A}\star w_{B})(\mathbf {x})\) and the expression

$$ K(\mathbf{x}_2,\mathbf{x}_1,\mathbf{x})=\text{Tr}[\hat{D}(\mathbf{x}_2)\hat{D}(\mathbf{x}_1)\hat{U}(\mathbf{x})] $$
(5)

called the kernel of the star-product [18]. Since the standard product of operators is associative, i.e. \(\hat {A}(\hat {B}\hat {C})=(\hat {A}\hat {B})\hat {C}\), the star-product of symbols of operators must be associative too

$$ w_A(\mathbf{x})\star (w_B\, \star w_C)(\mathbf{x})=(w_A\star w_B)(\mathbf{x})\star w_C(\mathbf{x}). $$
(6)

The associativity condition (6) in terms of the kernel of the star-product of symbols takes the form [20]

$$ \int K(\mathbf{x}_1,\mathbf{x}_2,\mathbf{y})K(\mathbf{y},\mathbf{x}_3,\mathbf{x}_4)d\mathbf{y}=\int K(\mathbf{x}_1,\mathbf{y},\mathbf{x}_4)K(\mathbf{x}_2,\mathbf{x}_3,\mathbf{y})d\mathbf{y}. $$
(7)

Let us suppose that there exists another pair of operators the quantizer \(\hat {D^{\prime }}(\mathbf {y})\) and the dequantizer \(\hat {U^{\prime }}(\mathbf {y})\) acting in \(\mathcal {H}\) and labeled by a vector with \(m\) components \(\mathbf {y}=(y_{1},y_{2},\ldots ,y_{m})\). Using these operators, for the operator \(\hat {A}\) one can associate another function different from (1)

$$ w^{\prime}_A(\mathbf{y})=\text{Tr}[\hat{A}\,\hat{U^{\prime}}(\mathbf{y})], $$
(8)

the inverse relation is

$$ \hat{A}=\int w^{\prime}_A(\mathbf{y})\hat{D}^{\prime}(\mathbf{y})d\mathbf{y}. $$
(9)

Since the functions \(w_{A}(\mathbf {x})\) and \(w^{\prime }_{A}(\mathbf {y})\) are symbols of the same operator \(\hat {A}\), one can obtain by inserting (2) into (8) [18]

$$ w^{\prime}_A(\mathbf{y})=\int w_A(\mathbf{x})\text{Tr}[\hat{D}(\mathbf{x})\hat{U}^{\prime}(\mathbf{y})]d\mathbf{x}. $$
(10)

The latter formula provides the relation between symbols corresponding to different maps. Similarly, using formulae (1) and (9), one gets the inverse relation

$$ w_A(\mathbf{x})=\int w^{\prime}_A(\mathbf{y})\text{Tr}[\hat{D}^{\prime}(\mathbf{y})\hat{U}(\mathbf{x})]d\mathbf{y}. $$
(11)

Using the definition of the star-product kernel (5), one gets that the kernels corresponding to different maps are connected to each other by the following relation

$$\begin{array}{@{}rcl@{}} K^{\prime}(\mathbf{y}_{1},\mathbf{y}_{2},\mathbf{y}_{3})&=&\int K(\mathbf{x}_{1},\mathbf{x}_{2},\mathbf{x}_{3})\text{Tr}[\hat{D}^{\prime}(\mathbf{y}_{1})\hat{U}(\mathbf{x}_{1})]\text{Tr}[\hat{D}^{\prime}(\mathbf{y}_{2})\hat{U}(\mathbf{x}_{2})] \\ &&\times\text{Tr}[\hat{U}^{\prime}(\mathbf{y}_{3})\hat{D}(\mathbf{x}_{3})]d\mathbf{x}_{1}d\mathbf{x}_{2}d\mathbf{x}_{3}, \end{array} $$
(12)

where \(K^{\prime }(\mathbf {y}_{1},\mathbf {y}_{2},\mathbf {y}_{3})=\text {Tr}[\hat {D}^{\prime }(\mathbf {y}_{1})\hat {D}^{\prime }(\mathbf {y}_{2})\hat {U}^{\prime }(\mathbf {y}_{3})]\).

In [21] the particular map was considered

$$ \hat{U}^d(\mathbf{x})=\hat{D}(\mathbf{x}),\quad \hat{D}^d(\mathbf{x})=\hat{U}(\mathbf{x}), $$
(13)

where the authors have exchanged the dequantizer \(\hat {U}(\mathbf {x})\) and the quantizer \(\hat {D}(\mathbf {x})\) by each other. The new pair quantizer-dequantizer is called dual to the initial one. The dual symbol of any operator \(\hat {A}\) is defined as

$$ w^{d}_A(\mathbf{x})=\text{Tr}[\hat{A}\,\hat{U}^d(\mathbf{x})]=\text{Tr}[\hat{A} \,\hat{D}(\mathbf{x})]. $$
(14)

The reconstruction formula for the operator \(\hat {A}\) is given by

$$ \hat{A}=\int w^{d}_A(\mathbf{x})\hat{D^d}(\mathbf{x})d\mathbf{x}=\int w^{d}_A(\mathbf{x})\hat{U}(\mathbf{x})d\mathbf{x}. $$
(15)

The dual operators provide a new associated star-product with the kernel

$$ K^d(\mathbf{x}_2,\mathbf{x}_1,\mathbf{x})=\text{Tr}[\hat{D^d}(\mathbf{x}_2)\hat{D^d}(\mathbf{x}_1)\hat{U^d}(\mathbf{x})]=\text{Tr}[\hat{U}(\mathbf{x}_2)\hat{U}(\mathbf{x}_1)\hat{D}(\mathbf{x})]. $$
(16)

The important property of the dual map is that the mean value of an observable \(\hat {A}\) is given by the product of the symbol of the density operator and the symbol of the observable in the dual representation

$$\begin{array}{@{}rcl@{}} \langle \hat{A}\rangle = \text{Tr} \hat{\rho}\hat{A}=\text{Tr}\left( \hat{A}\int w_{\rho}(\mathbf{x})\hat{D}(\mathbf{x})\, d\mathbf{x}\right)&=&\int w_{\rho}(\mathbf{x})\text{Tr}\left( \hat{A}\hat{D}(\mathbf{x})\right)\, d\mathbf{x}\\ &=&\int w_{\rho}(\mathbf{x}){w^{d}_{A}}(\mathbf{x})\, d\mathbf{x}, \end{array} $$
(17)

where \(w_{\rho }\) is the symbol of the density operator \(\hat {\rho }\), namely \(w_{\rho }(\mathbf {x})=\text {Tr}[\hat {\rho }\,\hat {U}(\mathbf {x})]\) (see (1)) and \({w^{d}_{A}}\) is the symbol of the observable \(\hat {A}\) in the dual representation.

3 Symplectic Tomographic and Center-of-Mass Maps

In this section we consider some special cases of tomographic maps, namely the symplectic, the center-of-mass and the dual center-of-mass maps. Here and throughout the paper we regard a quantum system with \(N\) degrees of freedom (for example, \(N=md\) for \(m\) particles in \(d\) dimension). Each vector has \(N\) components if otherwise stated. In the case of the symplectic map one choose \(\mathbf {x}=(\mathbf {X},\boldsymbol {\mu },\boldsymbol {\nu })\). The quantizer and the dequantizer for the symplectic map are given by the formula

$$ \hat{U}_{s}(\mathbf{X},\boldsymbol{\mu},\boldsymbol{\nu})=\delta(\mathbf{X}-\boldsymbol{\mu}\hat{\mathbf{q}}-\boldsymbol{\nu}\hat{\mathbf{p}}), $$
(18)
$$ \hat{D}_{s}(\mathbf{X},\boldsymbol{\mu},\boldsymbol{\nu})=(2\pi)^{-N}e^{i(\mathbf{e}\mathbf{X}-\boldsymbol{\mu}\hat{\mathbf{q}}-\boldsymbol{\nu}\hat{\mathbf{p}})}, $$
(19)

where \(\hat {\mathbf {q}}\) and \(\hat {\mathbf {p}}\) are the vectors with components \(\hat {q}_{j}\) and \(\hat {p}_{j}\) being the position and the momentum operators for each degree of freedom, the vector \(\mathbf {e}\) has all components equal to 1 and \(\mathbf {a}\,\mathbf {b}\) denotes scalar product of two vectors \(\mathbf {a}\) and b, \(\delta \) is the operator-valued Dirac \(\delta \)-function. The vector \(\mathbf {X}\) can be associated with the positions of the system in scaled and rotated reference frame in phase space, \(\boldsymbol {\mu }\) and \(\boldsymbol {\nu }\) are vectors with components \(\mu _{j}\) and \(\nu _{j}\) being real parameters of scaling and rotation. For any operator one can associate the tomographic symbol according to (1) and (18). By definition, the symplectic tomogram is the symbol of the density operator

$$ w_{s}(\mathbf{X},\boldsymbol{\mu},\boldsymbol{\nu})=\text{Tr}[\hat{\rho}\,\delta(\mathbf{X}-\boldsymbol{\mu}\hat{\mathbf{q}}-\boldsymbol{\nu}\hat{\mathbf{p}})]. $$
(20)

According to formula (2), the density operator can be reconstructed from the symplectic tomogram

$$ \hat{\rho}=(2\pi)^{-N}\int w_{s}(\mathbf{X},\boldsymbol{\mu},\boldsymbol{\nu}) e^{i(\mathbf{e}\mathbf{X}-\boldsymbol{\mu}\hat{\mathbf{q}}-\boldsymbol{\nu}\hat{\mathbf{p}})} d\mathbf{X} d\boldsymbol{\mu}\, d\boldsymbol{\nu}. $$
(21)

The state of a system with \(N\) degrees of freedom can be described by the density matrix of \(2N\) variables. In view of (20) and (21), the same state can be either described by the symplectic tomogram, which is a nonnegative function of \(3N\) variables, which is less convenient for large \(N\). This due to the fact that the symplectic tomogram has extra variables, which do not give additional information about the quantum system. However, in [11] the authors constructed the map called the center-of-mass map which allows to circumvent this problem. In the case of the center-of-mass map \(\mathbf {x}=(\xi ,\boldsymbol {\mu },\boldsymbol {\nu })\), where \(\xi \) is a real variable. The quantizer and the dequantizer are of the form

$$ \hat{U}_{cm}(\xi,\boldsymbol{\mu},\boldsymbol{\nu})=\delta(\xi-\boldsymbol{\mu}\hat{\mathbf{q}}-\boldsymbol{\nu}\hat{\mathbf{p}}), $$
(22)
$$ \hat{D}_{cm}(\xi,\boldsymbol{\mu},\boldsymbol{\nu})=(2\pi)^{-N}e^{i(\xi-\boldsymbol{\mu}\hat{\mathbf{q}}-\boldsymbol{\nu}\hat{\mathbf{p}})}. $$
(23)

The dequantizer (22) and the quantizer (23) determine the center-of-mass kernel of the star-product

$$\begin{array}{@{}rcl@{}} K_{cm}(\xi_{1},\boldsymbol{\mu}_{1},\boldsymbol{\nu}_{1}, \xi_{2},\boldsymbol{\mu}_{2},\boldsymbol{\nu}_{2}, \xi_{3},\boldsymbol{\mu}_{3},\boldsymbol{\nu}_{3})&\!\!=\!\!&(2\pi)^{-N-1} \exp\left[i(\xi_{1}\!+\!\xi_{2})\!+\!i(\boldsymbol{\nu}_{1}\boldsymbol{\mu}_{2}-\boldsymbol{\mu}_{1}\boldsymbol{\nu}_{2})/2\right]\\ &&\!\!\times\int e^{-i k \xi_{3}}\delta(\boldsymbol{\mu}_{1}+\boldsymbol{\mu}_{2}-k\boldsymbol{\mu}_{3})\,\delta(\boldsymbol{\nu}_{1}\!+\!\boldsymbol{\nu}_{2}\!-\!k\boldsymbol{\nu}_{3})\,dk.\notag\\ \end{array} $$
(24)

In the latter formula the integration of \(2N\) delta-functions is readily performed. For instance, in the case of two degrees of freedom \(\boldsymbol {\mu }_{i}=(\mu ^{(1)}_{i},\mu ^{(2)}_{i})\) and \(\boldsymbol {\nu }_{i}=(\nu ^{(1)}_{i},\nu ^{(2)}_{i})\), \(i = 1,2,3\) the center-of-mass kernel has the form

$$\begin{array}{@{}rcl@{}} K_{cm}(\xi_{1},\boldsymbol{\mu}_{1},\boldsymbol{\nu}_{1}, \xi_{2},\boldsymbol{\mu}_{2},\boldsymbol{\nu}_{2}, \xi_{3},\boldsymbol{\mu}_{3},\boldsymbol{\nu}_{3})&\!\!=\!\!&(2\pi)^{-3}\!\left|\nu^{(1)}_{3}\nu^{(2)}_{3}\mu^{(1)}_{3}\mu^{(2)}_{3}\right|^{-1}\\ &&\!\!\times\! \exp \left[i (\xi_{1}+\xi_{2})-i \xi_{3}(\nu^{(2)}_{1}+\nu^{(2)}_{2})/\nu^{(2)}_{3}\right.\\ &&\left.\!\!+i(\nu^{(1)}_{1} \mu^{(1)}_{2}-\mu^{(1)}_{1}\nu^{(1)}_{2}+\nu^{(2)}_{1} \mu^{(2)}_{2}-\mu^{(2)}_{1}\nu^{(2)}_{2})/2\right] \\ &&\!\!\times \delta \left( \frac{\mu^{(1)}_{1}+\mu^{(1)}_{2}}{\mu^{(1)}_{3}}-\frac{\nu^{(2)}_{1}+\nu^{(2)}_{2}}{\nu^{(2)}_{3}} \right)\\ &&\!\!\times\delta \left( \frac{\mu^{(2)}_{1}+\mu^{(2)}_{2}}{\mu^{(2)}_{3}}-\frac{\nu^{(2)}_{1}+\nu^{(2)}_{2}}{\nu^{(2)}_{3}} \right)\\ &&\!\!\times\delta \left( \frac{\nu^{(1)}_{1}+\nu^{(1)}_{2}}{\nu^{(1)}_{3}}-\frac{\nu^{(2)}_{1}+\nu^{(2)}_{2}}{\nu^{(2)}_{3}} \right). \end{array} $$
(25)

The center-of-mass tomogram is defined as the symbol of the density operator

$$ w_{cm}(\xi,\boldsymbol{\mu},\boldsymbol{\nu})=\text{Tr}[\hat{\rho}\,\delta(\xi-\boldsymbol{\mu}\hat{\mathbf{q}}-\boldsymbol{\nu}\hat{\mathbf{p}})]. $$
(26)

According to formula (2), the density operator can be reconstructed from the center-of-mass tomogram

$$ \hat{\rho}=(2\pi)^{-N}\int w_{cm}(\xi,\boldsymbol{\mu},\boldsymbol{\nu}) e^{i(\xi-\boldsymbol{\mu}\hat{\mathbf{q}}-\boldsymbol{\nu}\hat{\mathbf{p}})} d\xi d\boldsymbol{\mu}\, d\boldsymbol{\nu}. $$
(27)

Formulae (26) and (27) determine the invertible map between the tomogram \(w_{cm}(\xi ,\boldsymbol {\mu },\boldsymbol {\nu })\) and the density operator of the system. Therefore, the quantum state of a system with \(N\) degrees of freedom can be described by the nonnegative function with \(2N + 1\) variables. Furthermore, the center-of-mass tomogram is a homogeneous function, namely w c m (λξ,λμ,λν) = |λ|− 1w c m (ξ,μ,ν) for any real \(\lambda \neq 0\), which follows from (26). Hence, the center-of-mass tomogram actually operates with \(2N\) variables as the density matrix does. However, unlike the latter, the center-of-mass tomogram is a nonegative function. Given the wave function of a pure system, the center-of-mass tomogram is determined by fractional Fourier transform of the wave function [11].

According to general scheme (10) and (11), the kernels relating symbols of the symplectic and the center-of-mass maps read

$$\begin{array}{@{}rcl@{}} \text{Tr}[\hat{D}_{cm}(\xi,\boldsymbol{\mu}_{1},\boldsymbol{\nu}_{1})\hat{U}_{s}(\mathbf{X},\boldsymbol{\mu}_{2},\boldsymbol{\nu}_{2})]&=&(2\pi)^{-N}e^{i \xi}\int e^{-i \mathbf{k}\mathbf{X}}\delta(\boldsymbol{\mu}_{1}-\mathbf{k}\circ\boldsymbol{\mu}_{2})\\ &&\times \delta(\boldsymbol{\nu}_{1}-\mathbf{k}\circ\boldsymbol{\nu}_{2})\,d\mathbf{k}, \end{array} $$
(28)
$$\begin{array}{@{}rcl@{}} \text{Tr}[\hat{D}_{s}(\mathbf{X},\boldsymbol{\mu}_{1},\boldsymbol{\nu}_{1})\hat{U}_{cm}(\xi,\boldsymbol{\mu}_{2},\boldsymbol{\nu}_{2})]&=&(2\pi)^{-1}e^{i\mathbf{e}\mathbf{X}}\int e^{-i k \xi}\delta(\boldsymbol{\mu}_{1}-k\boldsymbol{\mu}_{2})\\ &&\times \delta(\boldsymbol{\nu}_{1}-k \boldsymbol{\nu}_{2})\,d k. \end{array} $$
(29)

Here \(\mathbf {a}\circ \mathbf {b}\) denotes the component-wise product of vectors \(\mathbf {a}=(a_{1},a_{2},\ldots ,a_{N})\) and b = (b1,b2,…,b N ), i.e. the vector \((a_{1}b_{1},a_{2}b_{2},\ldots ,a_{N} b_{N})\). Symbols in the symplectic and the center-of-mass representations are related as follows

$$ w_{s}(\mathbf{X},\boldsymbol{\mu},\boldsymbol{\nu})=(2\pi)^{-N}\int w_{cm}(\xi,\mathbf{k}\circ\boldsymbol{\mu},\mathbf{k}\circ\boldsymbol{\nu})e^{i(\xi-\mathbf{k}\mathbf{X})}d\mathbf{k}d\xi $$
(30)

and

$$ w_{cm}(\xi,\boldsymbol{\mu},\boldsymbol{\nu})=\int w_{s}(\mathbf{X},\boldsymbol{\mu},\boldsymbol{\nu})\delta(\xi-\mathbf{e}\mathbf{X})d\mathbf{X}. $$
(31)

In derivation of the latter formula, we have used the homogeneity property of the symplectic tomogram w s (λX,λμ,λν) = |λ|Nw s (X,μ,ν), which is directly follows from (20) and the homogeneity property of delta-function.

Exchanging the role of the quantizer (22) and the dequantizer (23), i.e.

$$\begin{array}{@{}rcl@{}} \hat{U}^{d}_{cm}(\xi,\boldsymbol{\mu},\boldsymbol{\nu})=(2\pi)^{-N}e^{i(\xi-\boldsymbol{\mu}\hat{\mathbf{q}}-\boldsymbol{\nu}\hat{\mathbf{p}})} \end{array} $$
(32)
$$\begin{array}{@{}rcl@{}} \hat{D}^{d}_{cm}(\xi,\boldsymbol{\mu},\boldsymbol{\nu})=\delta(\xi-\boldsymbol{\mu}\hat{\mathbf{q}}-\boldsymbol{\nu}\hat{\mathbf{p}}), \end{array} $$
(33)

one obtains the symbol of an operator \(\hat {A}\) in the dual center-of-mass representation

$$ w^d_{A}(\xi,\boldsymbol{\mu},\boldsymbol{\nu})=(2\pi)^{-N}e^{i \xi}\text{Tr}\left[\hat{A}\,e^{-i(\boldsymbol{\mu}\hat{\mathbf{q}}+\boldsymbol{\nu}\hat{\mathbf{p}})}\right]. $$
(34)

The reconstruction formula provides the expression for the operator \(\hat {A}\) in terms of its dual symbol

$$ \hat{A}= \int w^d_{A}(\xi,\boldsymbol{\mu},\boldsymbol{\nu})\delta(\xi-\boldsymbol{\mu}\hat{\mathbf{q}}-\boldsymbol{\nu}\hat{\mathbf{p}})\,d\xi\,d\boldsymbol{\mu}\,d\boldsymbol{\nu} $$
(35)

The dual kernel for the center-of-mass scheme determined by (16) is expressed as follows

$$\begin{array}{@{}rcl@{}} K^{d}_{cm}(\xi_{1},\boldsymbol{\mu}_{1},\boldsymbol{\nu}_{1},\xi_{2},\boldsymbol{\mu}_{2},\boldsymbol{\nu}_{2},\xi_{3},\boldsymbol{\mu}_{3},\boldsymbol{\nu}_{3})&=&e^{i\xi_{3}}\int \exp \left[i k_{1}k_{2}(\boldsymbol{\mu}_{2}\boldsymbol{\nu}_{1}-\boldsymbol{\mu}_{1}\boldsymbol{\nu}_{2})/2+i(k_{1} \xi_{1}+k_{2} \xi_{2})\right]\\ &&\times\delta(k_{1}\boldsymbol{\mu}_{1}+k_{2}\boldsymbol{\mu}_{2}+\boldsymbol{\mu}_{3})\delta(k_{1}\boldsymbol{\nu}_{1}+k_{2}\boldsymbol{\nu}_{2}+\boldsymbol{\nu}_{3})\frac{dk_{1} dk_{2}}{4\pi^{2}}.\\ \end{array} $$
(36)

According to general rule (17), the mean value of a quantum observable \(\hat {A}\) is given by integration of the product of its dual symbol and the center-of-mass tomogram

$$ \langle \hat{A}\rangle = \int w_{cm}(\xi,\boldsymbol{\mu},\boldsymbol{\nu})w^d_{A}(\xi,\boldsymbol{\mu},\boldsymbol{\nu})\, d\xi\,d\boldsymbol{\mu}\,d\boldsymbol{\nu}. $$
(37)

Since the center-of-mass tomogram has the property of a fair probability distribution, the dual symbol \({w^{d}_{A}}(\xi ,\boldsymbol {\mu },\boldsymbol {\nu })\) of the observable \(\hat {A}\) plays the role of the function identified with the observable in the center-of-mass scheme.

4 Weyl Map

In this section we present the general scheme that relates the center-of-mass tomographic map with the Weyl map providing an invertible map of operators onto functions on phase space (Weyl symbols). The Weyl map is the particular case of the star-product scheme and can be described by using the following pair of the dequantizer and the quantizer

$$ \hat{U}(\mathbf{q},\mathbf{p})=\int e^{-i\mathbf{p}\mathbf{u}}\left|\mathbf{q}-\frac{\mathbf{u}}{2}\right\rangle \left\langle \mathbf{q}+\frac{\mathbf{u}}{2}\right|d\mathbf{u}, $$
(38)
$$ \hat{D}(\mathbf{q},\mathbf{p})=(2\pi)^{-N} \hat{U}(\mathbf{q},\mathbf{p}). $$
(39)

The Weyl symbol of an operator \(\hat {A}\) is defined as follows

$$ w_{A}(\mathbf{q},\mathbf{p})=\text{Tr}\left[ \hat{A}\,\hat{U}(\mathbf{q},\mathbf{p})\right]= \int e^{-i\mathbf{p}\mathbf{u}}\left\langle \mathbf{q}+\frac{\mathbf{u}}{2}\right| \hat{A} \left|\mathbf{q}-\frac{\mathbf{u}}{2}\right\rangle d\mathbf{u}. $$
(40)

The operator \(\hat {A}\) can be reconstructed from its Weyl symbol

$$ \hat{A}=\int w_{A}(\mathbf{q},\mathbf{p}) \hat{D}(\mathbf{q},\mathbf{p}) d\mathbf{q} d\mathbf{p}. $$
(41)

The Wigner function is defined as the Weyl symbol of the density operator, i.e.

$$ W(\mathbf{q},\mathbf{p})=\int e^{-i\mathbf{p}\mathbf{u}}\left\langle \mathbf{q}+\frac{\mathbf{u}}{2}\right| \hat{\rho} \left|\mathbf{q}-\frac{\mathbf{u}}{2}\right\rangle d\mathbf{u}. $$
(42)

The relation between symbols of the center-of-mass map and the Weyl map is given by (10) and (11)

$$ w_{A}(\xi,\boldsymbol{\mu},\boldsymbol{\nu})=(2\pi)^{-N}\int w_A(\mathbf{q},\mathbf{p}) \delta(\xi-\boldsymbol{\mu}\mathbf{q}-\boldsymbol{\nu}\mathbf{p})d\mathbf{q}d\mathbf{p}. $$
(43)

and

$$ w_A(\mathbf{q},\mathbf{p})=(2\pi)^{-N}\int w_{A}(\xi,\boldsymbol{\mu},\boldsymbol{\nu}) e^{i(\xi-\boldsymbol{\mu}\mathbf{q}-\boldsymbol{\nu}\mathbf{p})}d\xi d\boldsymbol{\mu} d\boldsymbol{\nu}. $$
(44)

For the case of the density operator, i.e. \(\hat {A}=\hat {\rho }\), one obtains the relation between the center-of-mass tomogram and the Wigner function

$$ w_{cm}(\xi,\boldsymbol{\mu},\boldsymbol{\nu})=(2\pi)^{-N}\int W(\mathbf{q},\mathbf{p}) \delta(\xi-\boldsymbol{\mu}\mathbf{q}-\boldsymbol{\nu}\mathbf{p})d\mathbf{q}d\mathbf{p}. $$
(45)

The star-product of Weyl symbols

$$ (w_A\star w_B)(\mathbf{q}_3,\mathbf{p}_3)=\int G(\mathbf{q}_1,\mathbf{p}_1,\mathbf{q}_2,\mathbf{p}_2,\mathbf{q}_3,\mathbf{p}_3) w_A(\mathbf{q}_1,\mathbf{p}_1)w_B(\mathbf{q}_2,\mathbf{p}_2)d\mathbf{q}_1\,d\mathbf{q}_2\,d\mathbf{p}_1\,d\mathbf{p}_2 $$
(46)

is determined by the Grönewold kernel

$$ G(\mathbf{q}_1,\mathbf{p}_1,\mathbf{q}_2,\mathbf{p}_2,\mathbf{q}_3,\mathbf{p}_3)=\pi^{-2N}\exp \left[ 2i\left( \mathbf{q}_1\mathbf{p}_2-\mathbf{q}_2\mathbf{p}_1+\mathbf{q}_2\mathbf{p}_3-\mathbf{q}_3\mathbf{p}_2+\mathbf{q}_3\mathbf{p}_1-\mathbf{q}_1\mathbf{p}_3 \right)\right]. $$
(47)

Using (12), one obtains the relation between the Grönewold and the center-of-mass kernels

$$\begin{array}{@{}rcl@{}} K_{cm}(\xi_{1},\boldsymbol{\mu}_{1},\boldsymbol{\nu}_{1}, \xi_{2},\boldsymbol{\mu}_{2},\boldsymbol{\nu}_{2}, \xi_{3},\boldsymbol{\mu}_{3},\boldsymbol{\nu}_{3})=(2\pi)^{-3N}e^{i(\xi_{1}+\xi_{2})} \int G(\mathbf{q}_{1},\mathbf{p}_{1},\mathbf{q}_{2},\mathbf{p}_{2},\mathbf{q}_{3},\mathbf{p}_{3})\\ \times\exp\left[-i(\boldsymbol{\mu}_{1}\mathbf{q}_{1}+\boldsymbol{\mu}_{2}\mathbf{q}_{2}+\boldsymbol{\nu}_{1}\mathbf{p}_{1}+\boldsymbol{\nu}_{2}\mathbf{p}_{2})\right] \delta (\xi_{3}-\boldsymbol{\mu}_{3}\mathbf{q}_{3}-\boldsymbol{\nu}_{3}\mathbf{p}_{3})d\mathbf{q}_{1}d\mathbf{p}_{1}d\mathbf{q}_{2}d\mathbf{p}_{2}d\mathbf{q}_{3}d\mathbf{p}_{3}.\\ \end{array} $$
(48)

In the standard classical mechanics formalism multiplication of functions on phase-space is given by the pointwise commutative and associative product

$$ w_A(\mathbf{q},\mathbf{p})\cdot w_B(\mathbf{q},\mathbf{p})=\int w_A(\mathbf{q}_1,\mathbf{p}_1) w_B(\mathbf{q}_2,\mathbf{p}_2) K_{cl}(\mathbf{q}_1,\mathbf{p}_1,\mathbf{q}_2,\mathbf{p}_2,\mathbf{q},\mathbf{p})d\mathbf{q}_1\,d\mathbf{q}_2\,d\mathbf{p}_1\,d\mathbf{p}_2, $$
(49)

where the kernel reads

$$ K_{cl}(\mathbf{q}_1,\mathbf{p}_1,\mathbf{q}_2,\mathbf{p}_2,\mathbf{q},\mathbf{p})=\delta (\mathbf{q}-\mathbf{q}_1)\delta (\mathbf{q}-\mathbf{q}_2)\delta (\mathbf{p}-\mathbf{p}_1)\delta (\mathbf{p}-\mathbf{p}_2). $$
(50)

It was shown in [22] that the kernel of the pointwise product is the limit \(\hbar \rightarrow 0\) of the Grönewold kernel with the Planck constant reinserted. Thus, in quantum mechanics the star-product of functions on phase-space is determined by the Grönewold kernel, whereas in classical mechanics functions on phase-space are multiplied according to the pointwise product. It worth noting that for two particles kernel (25), where the term in the exponent \(\mu ^{(1)}_{1}\nu ^{(1)}_{2}-\nu ^{(1)}_{1}\mu ^{(1)}_{2}+\mu ^{(2)}_{1}\nu ^{(2)}_{2}-\nu ^{(2)}_{1}\mu ^{(2)}_{2}\) is removed corresponds to the point-wise product of functions on phase-space. This statement can be proven by inserting (50) into (48) and taking the integrals.

5 Cluster Tomogram

One can generalize the scheme of the center-of-mass map. To do that let us consider a quantum system with \(N\) degrees of freedom composed of \(r\) subsystems with \(k\)th subsystem having \(N_{k}\) degrees of freedom (of course, the following equality holds \(N=N_{1}+N_{2}+\ldots +N_{r}\)). For each subsystem we construct the dequantizer and the quantizer of the center-of-mass map (22) and (23), namely \(\hat {U}_{k}=\delta \left (\xi _{k}- \boldsymbol {\mu }_{k}\,\hat {\mathbf {q}}_{k}+\boldsymbol {\nu }_{k}\,\hat {\mathbf {p}}_{k}\right )\) and \(\hat {D}_{k}=(2\pi )^{-N_{k}}\exp {\left (\xi _{k}- \boldsymbol {\mu }_{k}\,\hat {\mathbf {q}}_{k}+\boldsymbol {\nu }_{k}\,\hat {\mathbf {p}}_{k}\right )}, \) where μ k and ν k are the \(N_{k}\) -component vectors with entries \(\mu _{k}^{(i)}\) and \(\nu _{k}^{(i)}\), \(i = 1,\ldots ,N_{k}\), \(\hat {\mathbf {q}}_{k}\) and \(\hat {\mathbf {p}}_{k}\) are the \(N_{k}\)-component vectors with entries \(\hat {q}_{k}^{(i)}\) and \(\hat {p}_{k}^{(i)}\) being the position and the momentum operators for \(k\)th subsystem. Here \(\xi _{k}\) is the sum of the positions of \(k\)th subsystem measured in rotated and scaled reference frame in phase space, \(\mu _{k}^{(i)}\) and \(\nu _{k}^{(i)}\) being the real parameters of scaling and rotation. Let us introduce the \(r\) - component vector ξ = (ξ1,ξ2,…,ξ r ) and the \(N\) - component vectors \(\boldsymbol {\mu }=(\boldsymbol {\mu }_{1},\boldsymbol {\mu }_{2},\ldots , \boldsymbol {\mu }_{r}) \), ν = (ν1,ν2,…,ν r ). With the composed system (cluster) we associate the dequantizer and the quantizer as product of the dequantizer and the quantizer of each subsystem, respectively

$$ \hat{U}_{cl}(\boldsymbol{\xi},\boldsymbol{\mu},\boldsymbol{\nu})=\prod_{k = 1}^{r}\delta\left( \xi_k- \boldsymbol{\mu}_k\,\hat{\mathbf{q}}_k-\boldsymbol{\nu}_k\,\hat{\mathbf{p}}_k\right), $$
(51)
$$ \hat{D}_{cl}(\boldsymbol{\xi},\boldsymbol{\mu},\boldsymbol{\nu})=(2\pi)^{-N}\prod_{k = 1}^{r}\exp{\left( \xi_k- \boldsymbol{\mu}_k\,\hat{\mathbf{q}}_k-\boldsymbol{\nu}_k\,\hat{\mathbf{p}}_k\right)}. $$
(52)

It is worth noting that the cases \(r = 1\) and \(r=N\) correspond to the center-of-mass and the symplectic maps, respectively. The kernel corresponding to the quantizer and the dequantizer (52), (51) reads

$$\begin{array}{@{}rcl@{}} K_{cl}(\boldsymbol{\xi}^{\prime\prime},\boldsymbol{\mu}^{\prime\prime},\boldsymbol{\nu}^{\prime\prime},\boldsymbol{\xi}^{\prime},\boldsymbol{\mu}^{\prime},\boldsymbol{\nu}^{\prime},\boldsymbol{\xi},\boldsymbol{\mu},\boldsymbol{\nu})&\!=\!& (2\pi)^{-N-r}\exp \left[ i \mathbf{e}\,\left( \boldsymbol{\xi}^{\prime\prime}\!+\!\boldsymbol{\xi}^{\prime}\right) \!+\!i (\boldsymbol{\mu}^{\prime}\boldsymbol{\nu}^{\prime\prime}-\boldsymbol{\nu}^{\prime}\boldsymbol{\mu}^{\prime\prime})/2\right] \\ &&\!\!\!\!\times\int e^{-i\mathbf{k} \boldsymbol{\xi}} \delta\left( \boldsymbol{\mu}^{\prime\prime}+\boldsymbol{\mu}^{\prime}-\mathbf{k}\circ\boldsymbol{\mu} \right)\delta\left( \boldsymbol{\nu}^{\prime\prime}+\boldsymbol{\nu}^{\prime}-\mathbf{k}\circ\boldsymbol{\nu} \right) d\mathbf{k},\\ \end{array} $$
(53)

where \(\mathbf {k}=(k_{1},k_{2},\ldots ,k_{r})\) and \(\mathbf {e}=(1,1,\ldots ,1)\) are \(r\)-component vectors and kμ = (k1μ1,k2μ2,…,k r μ r ). The cluster tomogram of the composed system with the density operator \(\hat {\rho }\) is defined by

$$ w_{cl}(\boldsymbol{\xi},\boldsymbol{\mu},\boldsymbol{\nu})= \text{Tr}\left[ \hat{\rho}\, \hat{U}_{cl}(\boldsymbol{\xi},\boldsymbol{\mu},\boldsymbol{\nu})\right]= \text{Tr}\left[ \hat{\rho}\, \prod_{k = 1}^{r}\delta\left( \xi_k- \boldsymbol{\mu}_k\,\hat{\mathbf{q}}_k-\boldsymbol{\nu}_k\,\hat{\mathbf{p}}_k\right)\right]. $$
(54)

The tomogram \(w_{cl}(\boldsymbol {\xi },\boldsymbol {\mu },\boldsymbol {\nu })\) is a nonnegative normalized function

$$ \int w_{cl}(\boldsymbol{\xi},\boldsymbol{\mu},\boldsymbol{\nu}) d\boldsymbol{\xi}= 1. $$
(55)

The connection between the center-of-mass and the cluster tomogram reads

$$ w_{cl}(\boldsymbol{\xi},\boldsymbol{\mu},\boldsymbol{\nu})=(2\pi)^{-r}\int w_{cm}(Y,\mathbf{k}\circ\boldsymbol{\mu},\mathbf{k}\circ\boldsymbol{\nu})e^{i(Y-\mathbf{k}\boldsymbol{\xi})}d\mathbf{k}dY $$
(56)

and

$$ w_{cm}(Y,\boldsymbol{\mu},\boldsymbol{\nu})=\int w_{cl}(\boldsymbol{\xi},\boldsymbol{\mu},\boldsymbol{\nu})\delta(Y-\mathbf{e}\boldsymbol{\xi})d\boldsymbol{\xi}. $$
(57)

The state of \(m\)th subsystem is associated with the center-of-mass tomogram

$$ w_{cm}^{(m)}(\xi_m,\boldsymbol{\mu}_m,\boldsymbol{\nu}_m )=\int w_{cl}(\boldsymbol{\xi},\boldsymbol{\mu},\boldsymbol{\nu}) d\xi_1 \ldots d\xi_{m-1}d\xi_{m + 1}\ldots d\xi_{r}. $$
(58)

Using (56), one can obtain the expression for the center-of-mass tomogram of \(m\)th subsystem in terms of the center-of-mass tomogram of the composed system

$$ w_{cm}^{(m)}(\xi_m,\boldsymbol{\mu}_m,\boldsymbol{\nu}_m )=(2\pi)^{-1}\int w_{cm}\left( Y,k \widetilde{\boldsymbol{\mu}}^{(m)},k\widetilde{\boldsymbol{\nu}}^{(m)} \right) e^{i(Y-k\xi_m)}dk\,dY, $$
(59)

where the designation \(\widetilde {\boldsymbol {\mu }}^{(m)}\) means that all components of vector \(\boldsymbol {\mu }\) equal zero, except \(\boldsymbol {\mu }_{m}\), i.e. \(\widetilde {\boldsymbol {\mu }}^{(m)}=(\mathbf {0},\ldots ,\boldsymbol {\mu }_{m},\ldots ,\mathbf {0})\). As an example, let us consider a system with \(N\) degrees of freedom composed of two subsystems having \(N_{1}\) and \(N_{2}\) degrees of freedom (N = N1 + N2). The state of the composed system can be described both by the cluster tomogram \(w_{cl}(\boldsymbol {\xi },\boldsymbol {\mu },\boldsymbol {\nu })\) (ξ is a vector) and by the center-of-mass tomogram w c m (ξ,μ,ν) (ξ is real variable), where \(\boldsymbol {\mu }=(\boldsymbol {\mu }_{1},\boldsymbol {\mu }_{2})\), ν = (ν1,ν2) are \(N\)-component vectors, \(\boldsymbol {\mu }_{i}\) and \(\boldsymbol {\nu }_{i}\) are \(N_{i}\)-component vectors, ξ = (ξ1,ξ2). The state of the first subsystem is associated with the center-of-mass tomogram (58)

$$ w_{cm}^{(1)}(\xi_1,\boldsymbol{\mu}_1,\boldsymbol{\nu}_1 )=\int w_{cl}(\boldsymbol{\xi},\boldsymbol{\mu},\boldsymbol{\nu}) d\xi_2. $$
(60)

The expression for \(w_{cm}^{(1)}\) in terms of the center-of-mass tomogram of the composed system reads

$$ w_{cm}^{(1)}(\xi_1,\boldsymbol{\mu}_1,\boldsymbol{\nu}_1 )=(2\pi)^{-1}\int w_{cm}\left( Y,k \widetilde{\boldsymbol{\mu}}^{(1)}, k \widetilde{\boldsymbol{\nu}}^{(1)} \right) e^{i(Y-k\xi_1)}dk\,dY, $$
(61)

where \(\widetilde {\boldsymbol {\mu }}^{(1)}=(\boldsymbol {\mu }_{1},\mathbf {0})\) and \(\widetilde {\boldsymbol {\nu }}^{(1)}=(\boldsymbol {\nu }_{1},\mathbf {0})\), all \(N_{2}\) components of the vector 0 equal zero.

The simplest case of the cluster tomogram corresponds to the factorized density operator, i.e. \(\hat {\rho }=\hat {\rho }_{1}\otimes \hat {\rho }_{2}\otimes \ldots \otimes \hat {\rho }_{r}\)

$$ w_{cl}(\boldsymbol{\xi},\boldsymbol{\mu},\boldsymbol{\nu})= \prod\limits_{m = 1}^{r}w_{cl}^{(m)}(\xi_m,\boldsymbol{\mu}_m,\boldsymbol{\nu}_m ). $$
(62)

Thus, the cluster tomogram for the systems without correlations is reduced to the products of the center-of-mass tomogram of each subsystems.

6 Joint Probability Distribution for the Center-of-Mass Tomogram

It was pointed out in the previous section that the state of a quantum system can be identified with the center-of-mass tomogram being the probability distribution of a random continuous variable \(\xi \) and extra parameters \(\mu _{j}\) and \(\nu _{j}\). It was indicated in [23] that the center-of-mass tomogram can be treated as conditional probability distribution, and corresponding notation is

$$ w_{cm}(\xi|\boldsymbol{\mu},\boldsymbol{\nu})\equiv w_{cm}(\xi,\boldsymbol{\mu},\boldsymbol{\nu}). $$
(63)

This interpretation follows from the fact that the center-of-mass tomogram satisfies so-called ‘no-signaling’ property (see, e.g., [23]).

$$ \int w_{cm}(\xi|\boldsymbol{\mu},\boldsymbol{\nu})\,d\xi = 1, $$
(64)

which holds true for any \(\boldsymbol {\mu }\) and ν. For the center-of-mass tomogram one can construct a joint probability of random variables \(\xi \), \(\boldsymbol {\mu }\) and \(\boldsymbol {\nu }\) in view of the Bayes formula (see, e.g., [24])

$$ \mathcal{W}(\xi,\boldsymbol{\mu},\boldsymbol{\nu})= w_{cm}(\xi|\boldsymbol{\mu},\boldsymbol{\nu})P(\boldsymbol{\mu},\boldsymbol{\nu}), $$
(65)

where \(P(\boldsymbol {\mu },\boldsymbol {\nu })\) is an arbitrary nonnegative normalized function \(\int P(\boldsymbol {\mu },\boldsymbol {\nu })d\boldsymbol {\mu } d\boldsymbol {\nu }= 1\). For example, one can take the Gaussian distribution function \(P(\boldsymbol {\mu },\boldsymbol {\nu })= \pi ^{-N}\exp {\left (-\boldsymbol {\mu }^{2}-\boldsymbol {\nu }^{2}\right )}\), where \(\boldsymbol {\mu }^{2}\) denotes the usual square of a vector \(\boldsymbol {\mu }\), i.e. \(\boldsymbol {\mu }^{2}=\sum {\mu _{i}^{2}}\). It is obviously that

$$ \int \mathcal{W}(\xi,\boldsymbol{\mu},\boldsymbol{\nu})d\xi = P(\boldsymbol{\mu},\boldsymbol{\nu}). $$
(66)

The nonnegative function \(\mathcal {W}(\xi ,\boldsymbol {\mu },\boldsymbol {\nu })\) is normalized with respect to all the variables, i.e.

$$ \int \mathcal{W}(\xi,\boldsymbol{\mu},\boldsymbol{\nu})d\xi d\boldsymbol{\mu} d\boldsymbol{\nu}= 1. $$
(67)

Inversely, given a joint probability distribution \(\mathcal {W}(\xi ,\boldsymbol {\mu },\boldsymbol {\nu })\) one can introduce the condition probability function

$$ w_{cm}(\xi|\boldsymbol{\mu},\boldsymbol{\nu})=\mathcal{W}(\xi,\boldsymbol{\mu},\boldsymbol{\nu})\left( \int \mathcal{W}(\xi,\boldsymbol{\mu},\boldsymbol{\nu})d\xi\right)^{-1}, $$
(68)

which satisfies the no-signaling property.

According to (27), the density matrix can be expressed in terms of the joint probability distribution

$$ \hat{\rho}=(2\pi)^{-N}\int \mathcal{W}(\xi,\boldsymbol{\mu},\boldsymbol{\nu})\left( \int \mathcal{W}(\xi,\boldsymbol{\mu},\boldsymbol{\nu})d\xi\right)^{-1}\exp{[i(\xi-\boldsymbol{\mu}\hat{\mathbf{q}}-\boldsymbol{\nu}\hat{\mathbf{p}})]}d\xi d\boldsymbol{\mu}\, d\boldsymbol{\nu}. $$
(69)

It follows from the latter formula that states of quantum systems can be associated with the joint probability distributions. Thus, there exist an ambiguity in constructing such probability distributions, which is related to the choice of the distribution function of random parameters.

7 Center-of-Mass Tomogram of the Two-Mode Schrödinger Cat States

Let us consider a system with two one-mode subsystems. The state of the composed system \(\hat {\rho }_{12}\) can be described both by the symplectic tomogram \(w_{s}(X_{1},X_{2},\mu _{1},\mu _{2},\nu _{1},\nu _{2})\) and by the center-of-mass tomogram \(w_{cm}(\xi ,\mu _{1},\mu _{2},\nu _{1},\nu _{2})\). The expression for the density operator \(\hat {\rho }_{12}\) in terms of the tomogram \(w_{cm}\) is given by (27)

$$ \hat{\rho}_{12}=(2\pi)^{-2}\int w_{cm}(\xi,\mu_1,\mu_2,\nu_1,\nu_2) e^{i(\xi-\mu_1\hat{q}_1-\mu_2\hat{q}_2-\nu_1\hat{p}_1-\nu_2\hat{p}_2)} d\xi d\mu_1\, d\mu_2\, d\nu_1 \,d\nu_2, $$
(70)

where \(\hat {q}_{i}\), \(\hat {p}_{i}\) are the position and the momentum operators for \(i\)th subsystem, \(i = 1,2\). The density operator of the first subsystem can be obtained by performing a trace over the second subsystem

$$ \hat{\rho}_{1}=\text{Tr}_2\,\hat{\rho}_{12}=(2\pi)^{-1}\int w_{cm}(\xi,\mu_1,0,\nu_1,0) e^{i(\xi-\mu_1\hat{q}_1-\nu_1\hat{p}_1)} d\xi d\mu_1\, d\nu_1. $$
(71)

The symplectic tomogram of the first subsystem reads

$$\begin{array}{@{}rcl@{}} w_{1}(X_{1},\mu_{1},\nu_{1})=\text{Tr}\hat{\rho}_{1}\delta(X_{1}-\mu_{1}\hat{q}_{1}-\nu_{1}\hat{p}_{1})\\ =(2\pi)^{-1}\int w_{cm}(\xi,k\mu_{1},0,k\nu_{1},0) e^{i(\xi-k X_{1})} dk\,d\xi. \end{array} $$
(72)

The latter formula corresponds to \(N_{1}=N_{2}= 1\) in (61).

Let us suppose that the composed system is entangled. As a measure of entanglement, we use the linear entropy defined as

$$ S_1 = 1-\text{Tr}\hat{\rho}^2_1. $$
(73)

The linear entropy ranges from 1, corresponding to a separable state, to 0 for a maximally entangled state. Inserting (71) into (73), one gets the expression for the linear entropy in terms of the center-of-mass tomogram

$$ S_1 = 1-(2\pi)^{-1}\int w_{cm}(\xi_1,\mu,0,\nu,0)w_{cm}(\xi_2,-\mu,0,-\nu,0) e^{i(\xi_1+\xi_2)} d\mu\,d\nu\,d\xi_1 d\xi_2. $$
(74)

As an example, let us consider the two-mode Schrödinger cat states, which are even and odd superpositions of coherent states with opposite phases [25]

$$ \psi_{\pm}(x_1,x_2)=N_{\pm}(\boldsymbol{\alpha})(\psi_{\boldsymbol{\alpha}}(x_1,x_2)\pm\psi_{-\boldsymbol{\alpha}}(x_1,x_2)). $$
(75)

The normalization constant is given by \(N_{\pm }^{-2}(\boldsymbol {\alpha })=(2\pm 2 e^{-2|\alpha _{1}|^{2}-2|\alpha _{2}|^{2}}) \). Here \(\psi _{\boldsymbol {\alpha }}(x_{1},x_{2})\) is the wave function of two-mode coherent state \(|\alpha _{1}\rangle |\alpha _{2}\rangle \) labeled by a complex vector \( \boldsymbol {\alpha }=(\alpha _{1},\alpha _{2})\)

$$ \psi_{\boldsymbol{\alpha}}(x_1,x_2)=\pi^{-N/4}\exp \left( -\frac{x^2_1+x^2_2}{2}+\sqrt{2}(\alpha_1 x_1+\alpha_2 x_2) -\frac{|\alpha_1|^2+|\alpha_2|^2}{2}-\frac{\alpha^2_1+\alpha^2_2}{2}\right). $$
(76)

Note that the states \(\psi _{\pm }(x_{1},x_{2})\) are entangled. The center-of-mass tomogram for the Schrödinger cat states can be calculated by means of the Wigner function (see (45)). Omitting the straightforward calculations, we obtain

$$\begin{array}{@{}rcl@{}} w^{\pm}_{cm,\boldsymbol{\alpha}}(\xi,\mu_{1},\mu_{2},\nu_{1},\nu_{2})=\pi^{-1/2}\sigma^{-1/2}N_{\pm}^{2}(\boldsymbol{\alpha})\\ \left\{ \exp{\left[-(\xi-\sqrt{2}\,\mathcal{R}\alpha_{1}\,\mu_{1}-\sqrt{2}\,\mathcal{R}\alpha_{2}\,\mu_{2}-\sqrt{2}\,\mathcal{I}\alpha_{1}\,\nu_{1}-\sqrt{2}\,\mathcal{I}\alpha_{2}\,\nu_{2})^{2}/ \sigma\right]}\right.\\ \pm\exp{\left[-2|\alpha_{1}|-2|\alpha_{2}|-(\xi-i\sqrt{2}\,\mathcal{I}\alpha_{1}\,\mu_{1}-i\sqrt{2}\,\mathcal{I}\alpha_{2}\,\mu_{2}+i\sqrt{2}\,\mathcal{R}\alpha_{1}\,\nu_{1}+i\sqrt{2}\,\mathcal{R}\alpha_{2}\,\nu_{2})^{2}/ \sigma\right]} \\ \pm\exp{\left[-2|\alpha_{1}|-2|\alpha_{2}|-(\xi+i\sqrt{2}\,\mathcal{I}\alpha_{1}\,\mu_{1}+i\sqrt{2}\,\mathcal{I}\alpha_{2}\,\mu_{2}-i\sqrt{2}\,\mathcal{R}\alpha_{1}\,\nu_{1}-i\sqrt{2}\,\mathcal{R}\alpha_{2}\,\nu_{2})^{2}/ \sigma\right]}\\ \left.+\exp{\left[-(\xi+\sqrt{2}\,\mathcal{R}\alpha_{1}\,\mu_{1}+\sqrt{2}\,\mathcal{R}\alpha_{2}\,\mu_{2}+\sqrt{2}\,\mathcal{I}\alpha_{1}\,\nu_{1}+\sqrt{2}\,\mathcal{I}\alpha_{2}\,\nu_{2})^{2}/ \sigma\right]}\right\} ,\\ \end{array} $$
(77)

where \(\mathcal {R}\alpha \) and \(\mathcal {I}\alpha \) denotes the real and the imaginary parts of complex variable \(\alpha \), \(\sigma ={\mu ^{2}_{1}}+{\mu ^{2}_{2}}+{\nu ^{2}_{1}}+{\nu ^{2}_{2}}\). The linear entropies of the Schrödinger cat states

$$ S_{\pm}(\alpha_1,\alpha_2)= 1-(2\pi)^{-1}\int w^{\pm}_{cm,\boldsymbol{\alpha}}(\xi_1,\mu,0,\nu,0)w^{\pm}_{cm,\boldsymbol{\alpha}}(\xi_2,-\mu,0,-\nu,0) e^{i(\xi_1+\xi_2)} d\mu\,d\nu\,d\xi_1 d\xi_2 $$
(78)

can be obtained by inserting (77) into (78) and are given by

$$ S_{\pm}(\alpha_1,\alpha_2)= 0.5-0.5\left( 1\pm e^{-2|\alpha_1|^2-2|\alpha_2|^2}\right)^{-2} \left( e^{-2|\alpha_1|^2}\pm e^{-2|\alpha_2|^2} \right)^2. $$
(79)

The linear entropies \(S_{\pm }(\alpha _{1},\alpha _{2})\) versus \(|\alpha _{1}|^{2}\) and various values of \(|\alpha _{2}|^{2}\) are depicted in Figs. 1 and 2. The entropy \(S_{+}(\alpha _{1},\alpha _{2})\) veries from 0 for \(|\alpha _{1}|= 0\) to \(0.5-0.5 e^{-4|\alpha _{2}|^{2}}\) for large values of \(|\alpha _{1}|\). The entropy \(S_{-}(\alpha _{1},\alpha _{2})\) increases from 0 to 0.5 corresponding to |α1| = |α2| and decreases to \(0.5-0.5 e^{-4|\alpha _{2}|^{2}}\) for large values of \(|\alpha _{1}|\).

Fig. 1
figure 1

The linear entropy S+(α1,α2) (79) for |α2|2 = 0.5 (solid line), |α2|2 = 1 (dashed line), |α2|2 = 2 (dotted line) and various values of |α1|2.

Fig. 2
figure 2

The linear entropy \(S_{-}(\alpha _{1},\alpha _{2})\) (79) for \(|\alpha _{2}|^{2}= 0.5\) (solid line), |α2|2 = 1 (dashed line), \(|\alpha _{2}|^{2}= 2\) (dotted line) and various values of \(|\alpha _{1}|^{2}\).

8 Conclusions

To conclude, we point out the main results of our work.

In this article we have considered the center-of-mass map of operators onto functions (tomographic symbols) in the context of the star-product formalism given by a pair of quantizer - dequantizer operators. These functions depend on one random variable \(\xi \) interpreted as `the center of mass’ coordinate of the quantum system under consideration in rotated and scaled reference frame in phase space and extra real parameters μ and \(\boldsymbol {\nu }\). The functions are multiplied according to a non-local and non-commutative product determined by the center-of-mass kernel (see (24)). We have obtained the connection between the kernels of the star-product corresponding to different maps, in particular we have given the relation between the center-of-mass and the Grönewold kernels. We have studied the dual center-of-mass map and derived the kernel corresponding to the star-product of operator symbols is given by this map.

The center-of-mass tomogram is defined as the function corresponding to the density operator of a quantum system. The center-of-mass tomogram being the probability distribution of \(\xi \) determines the quantum state completely in the sense that given the center-of-mass tomogram one can obtain the density operator. We have obtained the connection between the center-of-mass tomogram and the Wigner function. We have discussed the generalization of the center-of-mass tomogram (the cluster tomogram). In view of the fact that the center-of-mass tomogram satisfies ‘no-signaling’ property, the tomogram can be considered as the conditional probability distribution of random variable \(\xi \). The latter allows to construct a joint probability distribution of variables \(\xi \), \(\boldsymbol {\mu }\) and \(\boldsymbol {\nu }\) with the help of an arbitrary nonnegative normalized function P(μ,ν), which gives rise to an ambiguity in the center-of-mass description of quantum states.

We have considered an example of two-mode even and odd Schrödinger cat states in details.